csc^2x+cot^2x=1
Quadrant 3 Quadrant 4 Quadrant 2 Quadrant 1
-1
Quadrant one is the upper right quadrant, or where both X and Y are positive.
Assuming you want dx/dt and that the equation is x = cot(2) / t (i.e. cot(2) is a constant) we can use the power rule. First, we rewrite it: cot(2)/t = cot(2) * t-1 thus, by the power rule: dx/dt = (-1) cot(2) * t-1 -1 = - cot(2) * t-2= = -cot(2)/t2
It is -sqrt(1 + cot^2 theta)
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
1 quadrant = 1 quadrant. Or what is the question?
Quadrant 1: (1,5) Quadrant 2: (-2,3) Quadrant 3: (-3,-3) Quadrant 4:(4,-1)
csc^2x+cot^2x=1
Quadrant 3 Quadrant 4 Quadrant 2 Quadrant 1
5
quadrant 1
-1
Quadrant one is the upper right quadrant, or where both X and Y are positive.
Assuming you want dx/dt and that the equation is x = cot(2) / t (i.e. cot(2) is a constant) we can use the power rule. First, we rewrite it: cot(2)/t = cot(2) * t-1 thus, by the power rule: dx/dt = (-1) cot(2) * t-1 -1 = - cot(2) * t-2= = -cot(2)/t2
cot 15 = cot(45 - 30) = cot45.cot30 - 1 / cot45 + cot 30