in second and fourth... for angles 135 and 315 degrees
To simplify the expression ((1 - \cot(x))^2 \cot(x)), we start by expanding ((1 - \cot(x))^2) to get (1 - 2\cot(x) + \cot^2(x)). Then, we multiply this by (\cot(x)): [ (1 - 2\cot(x) + \cot^2(x)) \cot(x) = \cot(x) - 2\cot^2(x) + \cot^3(x). ] Thus, the simplified expression is (\cot(x) - 2\cot^2(x) + \cot^3(x)).
csc^2x+cot^2x=1
Quadrant 3 Quadrant 4 Quadrant 2 Quadrant 1
-1
Quadrant one is the upper right quadrant, or where both X and Y are positive.
It is -sqrt(1 + cot^2 theta)
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
1 quadrant = 1 quadrant. Or what is the question?
Quadrant 1: (1,5) Quadrant 2: (-2,3) Quadrant 3: (-3,-3) Quadrant 4:(4,-1)
csc^2x+cot^2x=1
Quadrant 3 Quadrant 4 Quadrant 2 Quadrant 1
5
quadrant 1
-1
Quadrant one is the upper right quadrant, or where both X and Y are positive.
Assuming you want dx/dt and that the equation is x = cot(2) / t (i.e. cot(2) is a constant) we can use the power rule. First, we rewrite it: cot(2)/t = cot(2) * t-1 thus, by the power rule: dx/dt = (-1) cot(2) * t-1 -1 = - cot(2) * t-2= = -cot(2)/t2
25% or 1/4, this is because it is a quadrant. Meaning a "quad" as in 4 therefore one quadrant is 1/4.