7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
first
2
Tan(Pi/5) = √(5-2*√(5)) ~= 0.7265
5
Pi / 5 would be in Quadrant I.
7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
first
-1
2
III
Tan(Pi/5) = √(5-2*√(5)) ~= 0.7265
5
(0-5) lies in First Quadrant
In which quadrant is the point (-5, 6)
The coordinate of (-12, 5) is in the 2nd quadrant
-3