to detect the sudden change in current.
IG=Betanx. in this G is G.constant, I is current, Be is Megnetic field of earth, OK? or anything else?
reduction factor is used to find earth's magnetic field and compare galvanometer constants
A common tangent is a line which is tangent to two (or more) curves.
dy/dx = (r - x)/sqrt(2xr - x2) , I hope!
Tangent 39 = 0.809784033195
because in tangent galvanometer earth magnetic field and magnetic field of magnet inside galvanometer are perpendicular to each other
it is the current measured in amphere..
reduction factor is used to find earth's magnetic field and compare galvanometer constants
IG=Betanx. in this G is G.constant, I is current, Be is Megnetic field of earth, OK? or anything else?
application of Ballistic Galvanometer 1) measurements of electric charges
helps people fly to the moon if they are short on cash. better shut up if u don't know the answer !!
by using the formula b=μn/2A(I/TAN Ɵ)....where μ=4πx10 pow(-7)n=number f turns of the coilA=radius of the coil(m)I=current flowing through the coil(A)Ɵ=angle of deflection in the tangent galvanometer.
1) to calculate coeficient of error 2) to calculate deviation between the readings to infere a behaviour
We find it by varying the current flowing through it and by measuring the deflection respectively and then we use the formula k=I/tan(theta)
Reduction factor of the tangent galvanometer is actually numerically equal towards the current in ampere needed to produce a deflection of 45° in it whenever the plane of the coil lies together the magnetic meridian.
A galvanometer is a simple meter that detects the flow of current. A current flowing in a wire causes magnetism around the wire. This is called electromagnetism. Like poles of a magnet repel and opposites attract. The Galvanometer uses these principles in order to move a pointer across a scale.
Assuming galvanometer has zero or negligible internal resistance. If u connect resistor R>>RL(Load resistance) and connect it parallel to RL, it will hardly cause any change in voltage across load resistance. Suppose small current Ig goes through galvanometer. Since galvanometer have zero internal resistance, Voltage across RL = Voltage across R = IgR