Octal numbers are in the range 0 to 7. Since 111 binary is 7 decimal, every three bits in a binary number can be directly converted to a single octal digit. Thus the 9-bit binary number 101011100 can be split into three groups of three bits, 101 011 100, each of which can be converted to octal, 5 3 4, making the octal representation 5348. If a binary number is not an exact multiple of 3 bits, pad with zeroes until it is. Note that all bases that are a power of 2 are directly related to binary. A single base-4 digit represents two binary digits, while a base-8 digit represents three bits, base-16 every four bits, and so on.
Yes.
BS 381C is not a colour, is a range of 'industrial' colours identified by a second three digit number
I am less than 100 so the range is 01 - 99, but as I am divisible by 2 then I am even. As my tens digit and ones digit are the same then I am a 2 digit number so the range is now 10 - 98. The sum of my digits is 8, my tens digit and my ones digit are the same . . so the only solution is 44.
-128 to 127
Octal numbers are in the range 0 to 7. Since 111 binary is 7 decimal, every three bits in a binary number can be directly converted to a single octal digit. Thus the 9-bit binary number 101011100 can be split into three groups of three bits, 101 011 100, each of which can be converted to octal, 5 3 4, making the octal representation 5348. If a binary number is not an exact multiple of 3 bits, pad with zeroes until it is. Note that all bases that are a power of 2 are directly related to binary. A single base-4 digit represents two binary digits, while a base-8 digit represents three bits, base-16 every four bits, and so on.
Repeatedly divide the number by 8 until the number is zero. Take the remainders from each division (the remainders will always be in the range 0 to 7 inclusive). The first division finds the lowest-order digit, the last finds the highest-order digit. Example: Decimal value: 421 421 / 8 = 52 r 5 52 / 8 = 6 r 4 6 / 8 = 0 r 6 The remainders are 6, 4 and 5, so 421 decimal is 645 octal. To convert from octal to decimal, multiply each octal digit by 8^n, where n is the zero-based order of the digit (0 being the lowest order), then sum the products. Example: Octal number: 645 5 * (8^0) = 5 * 1 = 5 4 * (8^1) = 4 * 8 = 32 6 * (8^2) = 6 * 64 = 384 384 + 32 + 5 = 421 Note that n^0 = 1 for all n>=0.
Yes.
BS 381C is not a colour, is a range of 'industrial' colours identified by a second three digit number
I am less than 100 so the range is 01 - 99, but as I am divisible by 2 then I am even. As my tens digit and ones digit are the same then I am a 2 digit number so the range is now 10 - 98. The sum of my digits is 8, my tens digit and my ones digit are the same . . so the only solution is 44.
Oh, dude, let me break it down for you. So, to find the number of 5-digit combinations from 1 to 60, you just do 60 minus 1 plus 1, which gives you 60. So, there are like 60 different 5-digit number combinations you can make from that range. Easy peasy, lemon squeezy!
-128 to 127
30.The first digit can be one of three digits {3, 6, 9} corresponding to the last digit being {1, 2, 3}, and for each of those three digits, the middle digit can be one of ten digits {0 - 9}, making 3 x 10 = 30 such numbers.It is assumed that a 3 digit number is a number in the range 100-999, excluding numbers starting with a leading zero, eg 090 is not considered a 3 digit number (though it would be a valid 3-digit number for a combination lock with 3 digits).
For any integer greater than 5, where the units digit is 5 then that number can be expressed as the product of n and 5. As such, the number is composite. Therefore all numbers in the range 150 to 200 that have a units digit of 5 are composite,.
A possible number range of 900,001 to 900,999 in every case the answer to your question is Zero.
Binary is a base 2 number system, while octal is base 8. This happens to make conversion between binary and octal fairly trivial, although more complex than conversion to hexadecimal. To convert to octal from binary, take each three bits, starting from the least significant bit, and convert them to their octal equivalent. Examples: 25510 = 111111112 = 11 111 111 = 3778 17410 = 101011102 = 10 101 110 = 2568 You can repeat this process for as many bits as you need. A 24-bit number should translate into 8 octal numbers, for reference.
The ones digit in even numbers can be any of the following: 0, 2, 4, 6, or 8. This is because even numbers are divisible by 2, meaning they can be expressed as 2 multiplied by another integer. The ones digit is the digit in the ones place of a number, which can range from 0 to 9.