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Assuming the missing operator before the final 5 is subtract, then:
x2 - 4x - 5 = (x + 1) (x - 5)
⇒ x = -1 or 5.
If it is add, there are no real root solution.
The solution to the latter case is:
x2 - 4x + 5 = (x - 2 - i)(x - 2 + i)
⇒ x = 2 + i or x = 2 - i.
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What is the value of m in 25x2-20x plus m equals 0 so that the two roots are equal?
4 and the two equal roots are 2/5 and 2/5
What is the value of k when kx squared plus 4x plus 5 equals 0 showing work?
k can have any value; however, the range of values permitted depends upon different things: The value of k depends on the value of x (ie given a value of x, the value of k can be calculated so that kx² + 4x + 5 = 0 has a root at that value of x): kx² + 4x + 5 = 0 => kx² = - 4x - 5 = -(4x + 5) => k = -(4x + 5)/x² Note that if x = 0, then the value of k is not determinable. Another possible answer using the discriminant of b²-4ac; from this the number of roots of the equation can be discovered: Two real roots: b²-4ac > 0 → 4² - 4×k×5 > 0 → 16 - 20k > 0 → 20k < 16 → k < 4/5 So for all values of k less than 4/5 there are two real roots of the quadratic kx² +4x + 5 = 0 One real repeated root: b² - 4ac = 0 → k = 4/5 So for k = 4/5, the quadratic (4/5)x² +4x +5 = 0 (→ 4x² +20x + 25 = 0) has one repeated real root. Two complex roots: b² - 4ac < 0 → k > 4/5 So for all values of k greater than 4/5 there are two complex roots of the quadratic kx² +4x + 5 = 0
What square roots applies to 25?
The square roots of 25 are 5 and -5
What are the roots of quadratic equation?
That depends on the value of its discriminant if its less than zero then it has no real roots.
What are the 2 main types of roots?
The two main roots in math are square roots and cubed roots. The square root is what number squared is your original number. For example the square root of 25 is 5 because 5 x 5 is 25. For cubed roots it is what numbered cubed is your original number.
What is the value of m in 25x2-20x plus m equals 0 so that the two roots are equal?
4 and the two equal roots are 2/5 and 2/5
What is the value of k when kx squared plus 4x plus 5 equals 0 showing work?
k can have any value; however, the range of values permitted depends upon different things: The value of k depends on the value of x (ie given a value of x, the value of k can be calculated so that kx² + 4x + 5 = 0 has a root at that value of x): kx² + 4x + 5 = 0 => kx² = - 4x - 5 = -(4x + 5) => k = -(4x + 5)/x² Note that if x = 0, then the value of k is not determinable. Another possible answer using the discriminant of b²-4ac; from this the number of roots of the equation can be discovered: Two real roots: b²-4ac > 0 → 4² - 4×k×5 > 0 → 16 - 20k > 0 → 20k < 16 → k < 4/5 So for all values of k less than 4/5 there are two real roots of the quadratic kx² +4x + 5 = 0 One real repeated root: b² - 4ac = 0 → k = 4/5 So for k = 4/5, the quadratic (4/5)x² +4x +5 = 0 (→ 4x² +20x + 25 = 0) has one repeated real root. Two complex roots: b² - 4ac < 0 → k > 4/5 So for all values of k greater than 4/5 there are two complex roots of the quadratic kx² +4x + 5 = 0
What square roots applies to 25?
The square roots of 25 are 5 and -5
Obtain fifth roots of 4 3i?
To find the fifth roots of 4 + 3i, first convert the number to polar form: 4 + 3i = 5∠36.87°. Then, to find the fifth roots, divide the angle by 5: 36.87° / 5 = 7.374°. The fifth roots in polar form are 5∠7.374°, 5∠67.374°, 5∠127.374°, 5∠187.374°, and 5∠247.374°.
If the sum of the roots of x2 3x-5x0 is added to the product of the roots?
Um, x2+3x-5=0? This is ax2+bx+c where a=1, b=3, and c=-5. The sum of the roots is -b/a so that means the sum of the roots is -3. Also, product of the roots is c/a. That means the product of the roots is -5. -3+(-5)= -8. There you have it.
What are the roots of quadratic equation?
That depends on the value of its discriminant if its less than zero then it has no real roots.
What are the 2 main types of roots?
The two main roots in math are square roots and cubed roots. The square root is what number squared is your original number. For example the square root of 25 is 5 because 5 x 5 is 25. For cubed roots it is what numbered cubed is your original number.
Do morning glories have tap roots or fibers roots?
Morning glories do not have tap roots. In zone 5, it is an annual. So they roots are not that deep.
What are the imaginary cube roots of -125?
This can be done easily if you use polar coordinates. I did all of the following calculations in my head, without resorting to a calculator: One of the cubic roots of -125 is -5. That is the same as 5, at an angle of 180 degrees. The other two cubic roots also have an absolute value of 5, and each cubic root has an angle of 120 degrees to the other cubic roots. In other words, the complex roots are 5 at an angle of 60 degrees, and 5 at an angle of -60 degrees. If you want to convert this to rectangular coordinates (i.e., show the real and the imaginary parts separately), use the P-->R (polar to rectangular) conversion, available on most scientific calculators.
What are the real fourth roots of 625?
5 and -5
What are the two sqaure roots of 25?
5 and -5.
What are 2 square roots of 25?
5 and -5
