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What is the value of m in 25x2-20x plus m equals 0 so that the two roots are equal?
4 and the two equal roots are 2/5 and 2/5
What is the value of k when kx squared plus 4x plus 5 equals 0 showing work?
k can have any value; however, the range of values permitted depends upon different things: The value of k depends on the value of x (ie given a value of x, the value of k can be calculated so that kx² + 4x + 5 = 0 has a root at that value of x): kx² + 4x + 5 = 0 => kx² = - 4x - 5 = -(4x + 5) => k = -(4x + 5)/x² Note that if x = 0, then the value of k is not determinable. Another possible answer using the discriminant of b²-4ac; from this the number of roots of the equation can be discovered: Two real roots: b²-4ac > 0 → 4² - 4×k×5 > 0 → 16 - 20k > 0 → 20k < 16 → k < 4/5 So for all values of k less than 4/5 there are two real roots of the quadratic kx² +4x + 5 = 0 One real repeated root: b² - 4ac = 0 → k = 4/5 So for k = 4/5, the quadratic (4/5)x² +4x +5 = 0 (→ 4x² +20x + 25 = 0) has one repeated real root. Two complex roots: b² - 4ac < 0 → k > 4/5 So for all values of k greater than 4/5 there are two complex roots of the quadratic kx² +4x + 5 = 0
What square roots applies to 25?
The square roots of 25 are 5 and -5
What are the roots of quadratic equation?
That depends on the value of its discriminant if its less than zero then it has no real roots.
What are the 2 main types of roots?
The two main roots in math are square roots and cubed roots. The square root is what number squared is your original number. For example the square root of 25 is 5 because 5 x 5 is 25. For cubed roots it is what numbered cubed is your original number.
