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What else can I help you with?
What 4 organs are found in plants?
there are four plant cells and they are 1 flower 2 stem 3 leaves 4 roots
What is the 4 letter biology term with where the second letter is t and the fifth letter is m?
Im sorry but you have posted your question wrong. You said its 4 ltters long so how can its fifth letter be m?
How deep do grass roots grow?
Grass roots typically grow to a depth of 4-6 inches, although some species can grow deeper. The depth of grass roots can also vary depending on soil conditions, climate, and grass species.
What phyla do flowering plants belong to?
A flowering plant also known as an angiosperm have roots, leaves and stems. They are either and monocot which has 3 petals branching roots and parallel vines, Or it is a diocot which has 4 or 5 petals trap roots and branching vines.
What is 750ml equal to?
It's close to a "fifth"Before the adoption of metric units, booze in the U.S. was most commonly bottled in quarts and "fifths." A quart is one quarter of a gallon, and a fifth is -- you guessed it -- a fifth of a gallon. Now, liquor comes in one-liter and 750-ml bottles, which are about the same size as the quart and fifth, respectively.A 750-ml bottle -- the most common size for wine -- is 0.750 liter. In other words, it's three quarters of a liter (because 3/4 = 0.75).One fifth of a US gallon is 25.6 ounces, and 0.75 liter equals 25.4 ounces, so a 750-ml bottle is very close to a fifth.
What is the polynomial roots to 1 5i and -3i?
4
Find the fourth complex roots of w equals 81 and plot them?
if the question is w^4 = 81 {w raised to the power of 4},Then the four roots are w = {3, -3, 3i, -3i}.The plots on the real-imaginary plane would be the points:(3,0)(-3,0)(0,3)(0,-3)
Find the multiplicative inverse of 4-3i?
7
What is the complex conjugate 3i plus 4?
The complex conjugate of a complex number is obtained by changing the sign of its imaginary part. For the complex number ( 3i + 4 ), which can be expressed as ( 4 + 3i ), the complex conjugate is ( 4 - 3i ).
What is the multiplicative inverse of 4 plus 3i?
Use the rules of division for complex numbers. Just divide 1 / (4 + 3i). This requires multiplying numerator and denominator of this fraction by (4 - 3i), to get a real number in the denominator.
What is the complex conjugate of 3i?
0+3i has a complex conjugate of 0-3i thus when you multiply them together (0+3i)(0-3i)= 0-9i2 i2= -1 0--9 = 0+9 =9 conjugates are used to eliminate the imaginary parts
Which polynomial has rational coefficients a leading leading coefficient of 1 and the zeros at 2-3i and 4?
There cannot be such a polynomial. If a polynomial has rational coefficients, then any complex roots must come in conjugate pairs. In this case the conjugate for 2-3i is not a root. Consequently, either (a) the function is not a polynomial, or (b) it does not have rational coefficients, or (c) 2 - 3i is not a root (nor any other complex number), or (d) there are other roots that have not been mentioned. In the last case, the polynomial could have any number of additional (unlisted) roots and is therefore indeterminate.
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 2 -4 and 1 plus 3i?
To write a polynomial function with real coefficients given the zeros 2, -4, and (1 + 3i), we must also include the conjugate of the complex zero, which is (1 - 3i). The polynomial can be expressed as (f(x) = (x - 2)(x + 4)(x - (1 + 3i))(x - (1 - 3i))). Simplifying the complex roots, we have ((x - (1 + 3i))(x - (1 - 3i)) = (x - 1)^2 + 9). Thus, the polynomial in standard form is: [ f(x) = (x - 2)(x + 4)((x - 1)^2 + 9). ] Expanding this gives the polynomial (f(x) = (x - 2)(x + 4)(x^2 - 2x + 10)), which can be further simplified to the standard form.
What is the answer to (7-3i plus 4 plus 8i)?
To simplify the expression ( (7 - 3i) + (4 + 8i) ), combine the real parts and the imaginary parts separately. The real parts are ( 7 + 4 = 11 ), and the imaginary parts are ( -3i + 8i = 5i ). Therefore, the answer is ( 11 + 5i ).
What are the real fifth roots of -4?
There's only one: -1.31951 (rounded)The other four are complex.
How do you do the math problem (4-3i)(5 2i)?
To multiply complex numbers you can use the same FOIL rule that you use for multiplying binomials (First, Inside, Outside, Last).(4 - 3i)(5 + 2i) = (4)(5) +(4)(2i) - (3i)(5) - (3i)(2i) = 20 + 8i-15i - 6(i)^2= 20 -7i - 6(-1) = 20 + 6 -7i = 26 -7i.
How do you solve complex fraction?
this is a very good question. lets solve (2+3i)/(4-2i). we want to make 4-2i real by multiplying it by the conjugate, or 4+2i (4-2i)(4+2i)=16-8i+8i+4=20, now we have (2+3i)/20 0r 1/10 + 3i/20 notice that -2i times 2i = -4i^2 =-4 times -1 = 4
