6 and 1/4 = 25/4
For an infinite geometric series, the sum ( S ) is given by the formula ( S = \frac{a_1}{1 - r} ), where ( a_1 ) is the first term and ( r ) is the common ratio. Given ( S = 6 ) and ( a_1 = 4 ), we can set up the equation ( 6 = \frac{4}{1 - r} ). Solving for ( r ), we get ( 6(1 - r) = 4 ), which simplifies to ( 6 - 6r = 4 ). Thus, ( 6r = 2 ) and ( r = \frac{1}{3} ).
24 hours = 1 day 6 hours = (6 / 24) = 1/4 of a day 1 day = four (1/4)s of a day 1 day is 4 times as long as 6 hours.
2/6 = 1/3 = 0.3333....recurring
6.25 = 6+(25/100) = 6+(1/4) = 25/4.
It is an alphanumeric sequence.
well 5/3 plus 1/3= 6/3. now you have to add 6/3 & 2/1 (2/1 = 2) you have to change the fraction(s) so you have to find the least common denominator so it is 6/3 plus 6/3= 12/3 =4/1 or 4
1/4 - 3/4 = -2/4 or -1/2
4 divided by 1/6 Re-write as 4/1 Divide 1/6 Remember for division of fractions ' Change the sign to multiply (X) and invert (turn over) the right hand fraction'. Hence 4/1 X 6/1 = 24/1 = 24 THe answer. NB This means that there are twenty four '1/6's' in '4'. Or you can think of it as In one whole unit there are six of 1/6 ( 6/6 = 1) So in four whole units there twenty four of 1/6 ( 24/6 = 4)/.
1, 2, 3, 4, 6, 12.
24 hours = 1 day 6 hours = (6 / 24) = 1/4 of a day 1 day = four (1/4)s of a day 1 day is 4 times as long as 6 hours.
2/6 = 1/3 = 0.3333....recurring
H is +1, O3 is -6, that is -5 -5 and the total charge is -1 so a -4 has to be contributed by S
First, it is going by ones: 1 2 3 4 5 6. Next it goes by 2's. 2 4 6 8. Finally it goes by 's. 6 9, next would be 12, 15.
Depends on the engine. Most V8's were 1-8-4-3-6-5-7-2. Slant 6's were 1-5-3-6-2-4 (I think)
6.25 = 6+(25/100) = 6+(1/4) = 25/4.
Mail Call - 2002 S-S- Lane Victory 6-4 was released on: USA: 1 April 2005
In this sequence s the nth term is s(n) calculated as follows where s(1) = 1: s(n) = (n - 1)(s(n - 1)) eg the 5th number (s(5)) = 4th number times 4 so next number s(7) will be 6 times s(6) ie 720