-66
The sequence can be generated by the following quartic:
t(n) = (-3n4 + 42n3 - 177n2 - 358n + 2808)/8 for n = 1, 2, 3, ...
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225.
17^(2) = 289 .
You will look in the numbers before you answer. Start in ones, next to tens, hundreds and thousands. If the number/s is/are least, write the least number. And count again. Count starting in ones, next is tens, hundreds and thousands,so remember it. So, 201 is the first, 289 is next, and the greatest number is 299. So, the arrangement of 201, 299 and 289 is 201, 289 and 299.
There is a mistake in the question -fourth number should not be 122² = 45² = 258² = 6411² = 121 (not 12)14² = 19617² = 289so add 3 to previous number then square it17 + 3 = 20then 20² = 400 next number
289 = 289/1