Q: What set sin loc from?

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Assume the expression is: 2sin²(x) + cos²(x) = 1 Use this identity to work out the problem: cos²(x) = 1 - sin²(x) Then: 2sin²(x) + 1 - sin²(x) = 1 sin²(x) + 1 = 1 sin²(x) = 0 sin(x) = 0 Therefore, the solutions are: x = πk radians where k belongs to the set of integers In degrees, we obtain: x = 180l° where l belongs to the set of integers

Any set that contains it. For example, the set {1, 2.3, 2.236067977} or {-79000, pi, 2.236067977, sin(47)} or all real numbers, etc

Sin Sin Sin was created on 2006-05-22.

cos*cot + sin = cos*cos/sin + sin = cos2/sin + sin = (cos2 + sin2)/sin = 1/sin = cosec

sin(3A) = sin(2A + A) = sin(2A)*cos(A) + cos(2A)*sin(A)= sin(A+A)*cos(A) + cos(A+A)*sin(A) = 2*sin(A)*cos(A)*cos(A) + {cos^2(A) - sin^2(A)}*sin(A) = 2*sin(A)*cos^2(A) + sin(a)*cos^2(A) - sin^3(A) = 3*sin(A)*cos^2(A) - sin^3(A)

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