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A shape where the perimeter is twice the area is a square. If we denote the side length of the square as ( s ), the perimeter ( P ) is ( 4s ) and the area ( A ) is ( s^2 ). Setting the perimeter equal to twice the area gives the equation ( 4s = 2s^2 ), which simplifies to ( s^2 - 2s = 0 ). This means ( s(s - 2) = 0 ), indicating that the side length can be 0 or 2, so a square of side length 2 has a perimeter of 8 and an area of 4, satisfying the condition.

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2mo ago

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