4 4 6 6 10
(3, 4, 6, 8, 9)
3 (15/5), 21/5, 27/5, 33/5, 39/5, 9(45/5) Range = 9 - 3 = 6 Mean = (15/5 + 21/5 + 27/5 + 33/5 + 39/5 + 45/5)/6 = (180/5)/6 = 36/6 = 6
{4,6,8}
8 and 4
4 4 6 6 10
I think this is impossible? 3.5 4.5 5.5 6.5 7.5 8.5 are 6 numbers that add to 36, have a a mean of 6 but a range of only 5.
(3, 4, 6, 8, 9)
To find two numbers with a mean of 10 and a range of 8, we can set up a system of equations. Let x be the smaller number and y be the larger number. We know that (x+y)/2 = 10 (mean of 10) and y-x = 8 (range of 8). Solving these equations simultaneously, we get x = 6 and y = 14. Therefore, the two numbers are 6 and 14.
What four numbers have a range of 8, and has the same mean and mediun
3,5,6,7,9
3 (15/5), 21/5, 27/5, 33/5, 39/5, 9(45/5) Range = 9 - 3 = 6 Mean = (15/5 + 21/5 + 27/5 + 33/5 + 39/5 + 45/5)/6 = (180/5)/6 = 36/6 = 6
{4,6,8}
6 (six)
6 + 14
12 and 8
8 and 4