Impossible.
The sum of the first six odd numbers is 36.
999999 is six digits and odd.
5+5+5+5+1 That is only 5 numbers being added. There can be no answer for six numbers for the following reasons: The numbers are all odd. Two odd numbers make an even number. Two even numbers make an even number. 21 is odd. Take 6 odd numbers and add them up in pairs. Each pair of odd numbers gives an even number so there are 3 even numbers. Even + Even + Even = Even. So sum of any six odd numbers is even but 21 is not even.
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
yes 100
Impossible.
There have to be an even number of odd numbers in each group, and each group must have more than two odd numbers (since 19 + 17 is only 36); thus there must be four in one group and six in the other. There are many ways to get four odd numbers to add up to to 50; for example, you could take 1, 13, 17 and 19. The remaining six odd numbers will then also add up to 50.
There are very many possible solutions. One such is: 1, 3, 5, 7, 9 and 75.
The sum of the first six odd numbers is 36.
999999 is six digits and odd.
5+5+5+5+1 That is only 5 numbers being added. There can be no answer for six numbers for the following reasons: The numbers are all odd. Two odd numbers make an even number. Two even numbers make an even number. 21 is odd. Take 6 odd numbers and add them up in pairs. Each pair of odd numbers gives an even number so there are 3 even numbers. Even + Even + Even = Even. So sum of any six odd numbers is even but 21 is not even.
If you have six boxes, with an odd number of coins in each box, in total you would have an EVEN number of coins. Therefore, this isn't possible. (odd + odd = even, odd + odd + odd = odd, etc. - if you add an even set of odd numbers, the total will always be even.)
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
All of the odd multiples of 9 are odd numbers. The largest odd multiple of 9 that's less than 100 is 99 ... the 11th multiple. So the ones that qualify are: 1, 3, 5, 7, 9, and 11 . . . six of them.
The sum of six odd numbers is never fifteen since 15 is odd and the sum of six even numbers is always even. However if "make" allows products: 1* 1 * 1 * 1 * 3* 5 = 15 ( I used * to mean multiply.)
Even. All numbers ending in six are even.