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By the Euler characteristic for polyhedra, F + V = E + 2
where F = # faces, E = # egdes, V = # vertices.
The equation implies that E - V = F - 2
Thus, if the polyhedron solid has more than two faces (it must have at least 4) then the right hand side is positive. So the left hand side must be positive. That is, E must be greater than V.
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A cube has more edges than vertices?
True. A cube has 12 edges and 8 vertices.
What shape has 4 more edges than vertices?
pyramid
Does a cube has more edges than vertices?
yes. a cube has 12 edges and 8 verticies
What solid figure has 4 more edges than vertices?
A triangular dipyramid (two tetrahedrons or triangular pyramids stuck together) has 9 edges and 5 vertices. A parallelepiped (including cuboid) has 12 edges and 8 vertices
A pyramid with a square base has how many more edges than vertices?
43 moreVertices:5 Edges:8 so 8-5=3 more edges
A cube has more edges than vertices?
True. A cube has 12 edges and 8 vertices.
What shape has 4 more edges than vertices?
pyramid
Does a cube has more edges than vertices?
yes. a cube has 12 edges and 8 verticies
A cube has how many more edges than vertices?
I don't know but I need to know =p
What shape has 6 faces 6 vertices and 9 edges?
The shape would be impossible. The faces and vertices have to add up to two more than the edges.
What solid figure has 4 more edges than vertices?
A triangular dipyramid (two tetrahedrons or triangular pyramids stuck together) has 9 edges and 5 vertices. A parallelepiped (including cuboid) has 12 edges and 8 vertices
Can a prism have seven more edges than it has vertices?
Oh, isn't that a happy little question! Let's think about it together. A prism has 2 bases and the same number of edges as the number of sides on those bases, plus the number of edges connecting the corresponding vertices on the bases. So, a prism can't have seven more edges than vertices because the number of edges is determined by the number of sides on the bases and the number of vertices.
A pyramid with a square base has how many more edges than vertices?
43 moreVertices:5 Edges:8 so 8-5=3 more edges
If a polyhedron has 10 more edges than vertices how many faces does it have?
Oh, dude, it's like a math riddle! So, if a polyhedron has 10 more edges than vertices, we can use Euler's formula: Faces + Vertices - Edges = 2. Since we know the relationship between edges and vertices, we can substitute that in and solve for faces. So, it would have 22 faces. Math can be fun... sometimes.
How many faces and vertices does a gemstone have with 22 edges?
The number of vertices and faces is 2 more than the number of Edges according to Euler's formula. So a gemstone with 22 edges must have a total of 24 faces and vertices.
How many more vertices's are there in a triangular prism than in a pyramid?
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges. A pyramid with an n-sided base will have n + 1 vertices, n + 1 faces, and 2n edges. 6 - 5 = 1 more
Does a hexahedron have 6 faces 12 edges and 8 vertices?
Not necessarily. A hexahedron has 6 faces.It can have 9 to 12 edges and the number of vertices is 4 fewer than the number of edges.
