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To find a missing term in a trinomial, you can use the relationship between the coefficients and the variables in the standard form of a quadratic, which is ( ax^2 + bx + c ). If you know two of the terms, you can solve for the missing term by rearranging the equation based on the known values. For example, if you have ( a ) and ( c ), you can find ( b ) by using the formula ( b = - (a + c) ) if the trinomial is set to zero. Alternatively, factoring or completing the square can also help identify the missing term.
Given the algebraic expression (3m - 2)2, use the square of a difference formula to determine the middle term of its product.
The term burst their banks means they surpassed their expectations.
There can be no missing term in a single number.
Not really. A term is a part of an expression.
To find a missing term in a trinomial, you can use the relationship between the coefficients and the variables in the standard form of a quadratic, which is ( ax^2 + bx + c ). If you know two of the terms, you can solve for the missing term by rearranging the equation based on the known values. For example, if you have ( a ) and ( c ), you can find ( b ) by using the formula ( b = - (a + c) ) if the trinomial is set to zero. Alternatively, factoring or completing the square can also help identify the missing term.
The expression does not come from Shakespeare.
The square of the previous term.
Only if the term under the radical (square root sign) can be simplified to a rational expression. For example, √(4x2).
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Given the algebraic expression (3m - 2)2, use the square of a difference formula to determine the middle term of its product.
DensityB.desnity0 0!! !\......./density
There can be no missing term in a single number.
The term burst their banks means they surpassed their expectations.
Not really. A term is a part of an expression.
The expression (x^2 - 5x + 25) is not a trinomial square. A trinomial square takes the form ((a - b)^2 = a^2 - 2ab + b^2), which would include a linear term with a coefficient that is double the product of (a) and (b). In this case, the constant term (25) is not the square of half the coefficient of (x) (which would be ((-\frac{5}{2})^2 = \frac{25}{4})). Thus, this expression does not fit the criteria for a trinomial square.