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The consecutive integers are 39, 40, and 41.

To solve this algebraically, note that consecutive numbers can be indicated by the variables x, x+1, and x+2.

For the sum x + (x+1) + (x+2) = 120,

3x +3 = 120

3x= 117

x= 39, followed by 40 and 41

39+40+41 = 120

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Q: What three consecutive numbers added together equal 120?
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