No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder
How about 27
1+4+3 = 8 which is not divisible by 3, so 143 is not divisible by 3. 8 ÷ 3 has remainder 2, so 143 ÷ 3 has remainder 2.
Yes, it is divisible by three, and more than that, there will be no remainder.
To check if a number is divisible by another number, we divide. When we divide, there cannot be a remainder. For example, is 9 divisible by 3? Yes, it is because 9 divided by 3 is 3 without a remainder. How about 4? No, because when we divide 4 by 3 there is a remainder of 1. nycfunction@yahoo.com sum of the numbers in the given digits should be divisible by 3.then we can say that it is divisible by 3.example :22344 is divisible by 3.since2+2+3+4+4=15.so the given digit is divisible by 3
No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder
How about 27
1+4+3 = 8 which is not divisible by 3, so 143 is not divisible by 3. 8 ÷ 3 has remainder 2, so 143 ÷ 3 has remainder 2.
Yes but it will have a remainder
Let three consecutive integers be n, n+1 and n+2. If n is divisible by 3 then n+1 and n+2 cannot be divisible by 3 as these numbers will respectively leave remainders of 1 and 2. If n is not divisible by 3 then it will leave a remainder of 1 or 2. If n leaves a remainder of 1, then n+1 leaves a remainder of 2 and n+2 is therefore divisible by 3. If n leaves a remainder of 2, then n+1 is divisible by 3 and n+2 is not divisible by 3 as it leaves a remainder of 1.
Yes, it is divisible by three, and more than that, there will be no remainder.
To check if a number is divisible by another number, we divide. When we divide, there cannot be a remainder. For example, is 9 divisible by 3? Yes, it is because 9 divided by 3 is 3 without a remainder. How about 4? No, because when we divide 4 by 3 there is a remainder of 1. nycfunction@yahoo.com sum of the numbers in the given digits should be divisible by 3.then we can say that it is divisible by 3.example :22344 is divisible by 3.since2+2+3+4+4=15.so the given digit is divisible by 3
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3
It is not EVENLY divisible by three. You can divide it by three, but you will have a remainder. 95347/3 = 31782.333333333...
Yes, but not without a remainder.
Not evenly because there will be a remainder