The integers are 53, 55 and 57.
Well, I don't believe this is the answer, but 55 works. 55+55+55=165.
Five times thirty-three is equal to 165.
3 odd integers must total an odd number. 3 consecutive odd integers must total a multiple of 3. The lowest number greater than 162 which satisfies these requirements is 165, ie 53 + 55 + 57
Neither 8 nor 7 are equal to 165. The only number equal to 165 is 165.
The integers are 53, 55 and 57.
The numbers are -83 and -82.
25, 26, 27, 28, 29, 30
Well, I don't believe this is the answer, but 55 works. 55+55+55=165.
Five times thirty-three is equal to 165.
3 odd integers must total an odd number. 3 consecutive odd integers must total a multiple of 3. The lowest number greater than 162 which satisfies these requirements is 165, ie 53 + 55 + 57
163, 164, 165 let the three consecutive numbers be (n-1), n & (n+1). Then: (n-1) + n + (n+1) = 492 ⇒ 3n = 492 ⇒ n = 164 ⇒ the three numbers are 164-1 = 163, 164 & 164+1 = 165.
√144 < √165 < √169 12 < √165 < 13
Neither 8 nor 7 are equal to 165. The only number equal to 165 is 165.
15 × 11 = 165
Yes. 165 is evenly divisible by three.
12 and 13