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F = m A

m = 0.19

A = 11

F = (0.19) x (11) = 2.09 newtons upward

But there is another force on the rocket = (m g) = (0.19) x (9.8) = 1.862 newtons downward.

The engine also has to cancel this force.

Total engine thrust required = (2.09 + 1.862) = 3.952 newtons.

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Q: What thrust does a 190 gram model rocket need in order to have a vertical acceleration of 11.0 meters per second squared on earth?
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