5 & 10
5 & -15
12 and -2
-15 and 5
-65
5 & 10
-4 and -6
5 & -15
65
The integers 2 and 10 have a product of 20 and a sum of 12.
The answer is -10 and -8. -8 + -10= -18 -8x-10 =80.
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
-10 + -8 = -18 -10 x -8 = 80 The two numbers are therefore -10 and -8.
-15 and 5.
Two consecutive integers whose sum is 19 is 10 & 9; 10+9 = 19.
12 and -2
-10 and -14