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Call the two numbers required m and n. Then from the problem statement, m = 25 - n (equation 1) and mn = 100 (equation 2). Substitute the expression for m in equation 1 into equation 2 to produce n(25 - n) = 100. Multiply out the left side to produce 25 n - n2 = 100. Multiply this equation by -1 and collect all terms on one side to produce n2 - 25n -100 = 0 (equation 3). Equation 3 factors into (n -20)(n-5) = 0, which is true when n = 20 or n = 5. From equation 1 again, this means m = 5 or 20 respectively. Therefore, the two numbers required are 5 and 20.
Check: 5 + 20 = 25; 5 X 20 = 100.
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What 3 prime numbers added together equals 100?
Given that the total you are looking for is even, and that you are looking for three numbers in your solution, one of the numbers has to be 2 - otherwise, three odd numbers added together would always equal an odd number. The other two numbers in the sum are 37 and 61.
What is 29.47 equals?
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What 2 prime numbers added together equal 289?
289 is an odd number so it must be the sum of an odd and an even number. The only even prime number is 2 so the other number must be 287, which is not prime as it is divisible by 7, so your question has no answer in this universe.
When you add two prime numbers why do you get an even number?
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