Q: What two numbers are divisible by 4?

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numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4

There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.

None of these two numbers are divisible by 8.

For any number to be divisible by 4, the last two numbers have to be divisible by 4. In this instance, since the last two digits of this number are 96, and 96/4 = 24, we know that 1196 is divisible by 4.

Yes 1124 is divisible by 4. Since 24 is divisible by 4 1124 is divisible by 4. If the last two numbers of a number are divisible by 4, the number is divisible by 4. 24 divided by 4 is 6.

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No. If the last two numbers are not divisible by 4, then the number is not divisible by 4.

There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.

2: 2,4,6,8,10,12,14,16,18,20...4: 4,8,12,16,20,24,28,32,36,40...Half of all numbers divisible by 2 are divisible by 4.All numbers divisible by 4 are divisible by 2.

No.

The numbers that are divisible by two are infinite. The first four are: 2, 4, 6, 8.

Yes.

Whole numbers are divisible by 4 if the number formed by the last two individual digits is evenly divisible by 4. For example, the number formed by the last two digits of the number 2628 is 28, which is evenly divisible by 4 so the number 2628 is evenly divisible by 4.

Numbers for which the sum of the digits is divisible by 9. This is also true for 3. There are other divisibility/multiple tests for other numbers (e.g., numbers that are divisible by 5 end in 5 or 0; numbers whose last two digits are divisible by 4 are divisible by 4)

Yes, that is true.

There is no possible answer. The sum of two consecutive even numbers MUST leave a remainder of 2 when divided by 4. That is, the sum must be divisible by 2 but must not be divisible by 4.

A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.

two NUMBERS that are divisible by three are 6 and 9.