1 and 0 would be the smallest whole numbers that meet that condition: 12 - 02 = 13 13 - 03 = 12
#include <iostream>02using namespace std; 03 04int main() 05{ 06 int sum = 0; 07 int average = 0; 08 int array[10] = {1,2,3,4,5,6,7,8,9,10}; 09 for (int i = 0; i < 10; ++i) 10 sum+=array[i]; 11 average = sum/10; 12 cout<<"Average:"<<average; 13}
1/800 or 1.25x10 -03
Assuming that 00, 01, 02, etc. count as two digit numbers, then there are one hundred (1 through 99 and including 0).If you are not allowed to count 00, 01, 02, 03, 04, 05, 06, 07, 08, or 09 because they simplify to one digit numbers, then you have ten less--so a total of ninety two digit numbers.
The Two Ronnies Sketchbook was created on 2005-03-18.
Add them together to get the answer.
1 and 0 would be the smallest whole numbers that meet that condition: 12 - 02 = 13 13 - 03 = 12
.004 + 3 + .03 = 3.034
01 02 03 04 05 06 07 08 09
A Grounding in Numbers was created on 2010-04-03.
A World of Difference was created on 1960-03-11.
#include <iostream>02using namespace std; 03 04int main() 05{ 06 int sum = 0; 07 int average = 0; 08 int array[10] = {1,2,3,4,5,6,7,8,9,10}; 09 for (int i = 0; i < 10; ++i) 10 sum+=array[i]; 11 average = sum/10; 12 cout<<"Average:"<<average; 13}
03 14
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about .03 inches
Nokia c2-03 is a single sim phone where as nokia c2-03 is a duel sim phone.
two resistors r1=2000ohm,r2=4000ohm are joined in series and connected to a 100volt supply.the voltage drop across r1andr2 are measured successively by a voltmeter of resistance 50000ohm.find the sum of the two readings?