(737,3) (201,11) (67,33)
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1 & 1322 & 663 & 444 & 336 & 2211 & 12
What numbers would you like to be the next three? It is possible to find a polynomial of order 5 that will fit these three numbers and ANY other three numbers. For example, using the positin to value rule given by Un= -112.275n5 + 1,966.25n4 - 12,744.625n3 + 37,416.25n2 - 48,979.6 + 36,525 I can fit the numbers 1, 2 and 3 as the next three. So there are infinitely many possible answers to the question. Using the simplest rule, although the question does not require that, gives Un = 70n + 2001 and that requires the next three numbers to be 2281, 2351, 2421.
198198/9 = 2211*18 = 1986*33 = 198
11 is divisible by 11.11 times 2 is 22.11 < 2211 is deficient.13 is divisible by 4 and 13.The sum of 4 and 13 is 17.13 times 2 is 26.17 < 2613 is deficient.and so on...You just see what goes into the number (in this example, we use the numbers 11 and 13), then add them all together. Then you multiply the number you're investigating with 2, and if the result of this is greater than the sum, it is deficient.Let's check 12 (which is not deficient):12 is divisible by 2, 3, 4, 6, and 12The sum of 2, 3, 4, 6, and 12 is 2712 times 2 is 2424 < 27The sum is greater, so 12 is not deficient.
The area doesn't tell you the dimensions. There are an infinite number of differentdimensions that it could have, all with the same area.Here are a few. They ALL have 220 square inches of area inside:1 x 2202 x 1104 x 555 x 5510 x 2211 x 20