To answer this question, you first need to find all the unique sets of 4 numbers that add up to 6. These are:
0006
0051
0042
0033
0411
0321
0222
3111
2211
Now we need to find which of these can be ordered to give numbers between 1111 and 9999:
0006: 6000
0051: 1500, 5001, 5010, 5100
0042: 2004, 2040, 2400, 4002, 4020, 4200
0033: 3003, 3030, 3300
0411: 1104, 1140, 1401, 1410, 4011, 4101, 4110
0321: 1203, 1230, 1302, 1320, 2013, 2031, 2103, 2130, 2301, 2310, 3012, 3021, 3102, 3120, 3201, 3210
0222: 2022, 2202, 2220
3111: 1113, 1131, 1311, 3111
2211: 1122, 1212, 1221, 2112, 2121, 2211
These are all the numbers between 1111 and 9999 with a digit sum of 6.
There are 28706 such combinations. 5456 of these comprise three 2-digit numbers, 19008 comprise two 2-digit numbers and two 1-digit numbers, 4158 comprise one 2-digit number and four 1-digit numbers and 84 comprise six 1-digit numbers.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
There are 900 three digit numbers between 99 and 3,000 - ranging from 100 to 999
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
If you include the number 3,000, there are exactly 2,001 4-digit numbers between 500 and 3000.
That would be the numbers in the form "32x" (where "x" can be any digit). In other words, ten numbers.
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
There are no 3 digit numbers between 0 and 9 because 0 and 9 are 1 digit numbers.
use the digit 1234to make two different numbers
the diffrenece between two 3 digit numbers is a palindrome between 200 and 300. what are the numbers?
Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
There are 900 three-digit whole numbers between 1 and 1000
There are 900 three-digit numbers, all of which are between 99 and 3,000.
You can select 12 numbers for the first digit, 11 numbers for the second digit, and 10 numbers for the third digit; so 12*11*10 = 1320 sets of 3 numbers can be made out of 12 different numbers.
There are 28706 such combinations. 5456 of these comprise three 2-digit numbers, 19008 comprise two 2-digit numbers and two 1-digit numbers, 4158 comprise one 2-digit number and four 1-digit numbers and 84 comprise six 1-digit numbers.
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