1 x 40, 2 x 20, 4 x 10, 5 x 8
The two numbers can be 5 times 8 = 40
The numbers will be the square root of 1120
-34
There are no two real numbers that both multiply to give 25 and add to make 40. The two numbers would have to satisfy the equations ( x \times y = 25 ) and ( x + y = 40 ). However, solving these equations leads to a contradiction, as the maximum possible sum of two positive numbers that multiply to 25 is less than 40.
To find two numbers that multiply to 40 and add to -13, you can use the numbers -8 and -5. When multiplied, -8 × -5 equals 40, and when added, -8 + -5 equals -13. Thus, the numbers you're looking for are -8 and -5.
How about 40 and 1.
The two numbers can be 5 times 8 = 40
The numbers will be the square root of 1120
260
They are 40 and 40
There are no two real numbers that do. Using complex numbers, these two do: (-3/2 + i√151/2) & (-3/2 - i√151/2) Two numbers that add to -3 and multiply to -40 are -8 & 5 Two numbers that add to 3 and multiply to -40 are 8 & -5 Two complex numbers that add to 3 and multiply to 40 are (3/2 + i√151/2) & (3/2 - i√151/2)
27
-34
-452
The two numbers that add to -6 and multiply to -40 are -10 and 4. This is because -10 + 4 = -6 and -10 * 4 = -40. This type of problem can be solved by setting up a system of equations where the sum of the numbers is -6 and the product of the numbers is -40, then solving for the two numbers.
51
-43