000
One possibility: IV+IV+IV = XII using Roman numerals
There is no valid mathematical solution to the question.
1+2+3 6; 1X2X3 6
How about: 1*2*3 = 6 and 1+2+3 = 6
15
The number 2, in base 4 arithmetic.
The 4 numbers that give the same result when added or multiplied together are 1, 2, 3, and 6. When added together, they equal 12 (1 + 2 + 3 + 6 = 12), and when multiplied together, they also equal 12 (1 x 2 x 3 x 6 = 12). This is an example of a set of numbers that satisfy the condition of having the same sum and product.
Because 51 is an odd number, it cannot be totalled by adding the same number twice.
000
Two Numbers consisting only of ones that when multiplied or added equal the same number are 11, and 1.1
1, 2 and 3
One, two, and three.
The product of two numbers is the proceeding result when two numbers are added together.
one, two, and three
1, 2, 3
One possibility: IV+IV+IV = XII using Roman numerals