They are: 78 and 63
The two odd numbers that have a product of 141 are 3 and 47. This is because 3 multiplied by 47 equals 141, and both numbers are odd.
The numbers are 45, 47, and 49.
The number 141 is a product of two numbers that are factors of 141. To find these numbers, we need to factorize 141 into its prime factors, which are 3 and 47. Therefore, 3 times 47 equals 141.
141
The LCM of 3 and 47 is 141.
two prime numbers whose product is 141 = 3 & 47
The product of 141 multiplied by 47 is 6627
The two odd numbers that have a product of 141 are 3 and 47. This is because 3 multiplied by 47 equals 141, and both numbers are odd.
The numbers are 45, 47, and 49.
The greatest common multiple of any set of integers is infinite.
I don't think there's a solution to this problem. Let's work it through.Two consecutive integers: x & y. So y = x + 1.Product is 34 more than sum. Product (x*y) = sum(x+y) +34Substitute [y=x+1] into second equation: x*(x+1) = x + (x+1) + 34x2 + x = x + x + 1 + 34 --> x2 + x - 2*x - 35 = 0 --> x2 - x - 35 = 0 (quadratic)In the quadratic formula: a = 1, b = -1, c = -35, so we have (1 ± sqrt[1 - 4*(-35)])/(2*1) = (1 ± sqrt(141))/2; sqrt(141) is irrational, so the solution is not integers. Someone else can maybe check my work.
The number 141 is a product of two numbers that are factors of 141. To find these numbers, we need to factorize 141 into its prime factors, which are 3 and 47. Therefore, 3 times 47 equals 141.
Possible the simplest math question ever. -420 / 3 = -140. So the numbers you need are -139 , -140 , -141.
All integers greater than 1 are one or the other.
141
The LCM of 3 and 47 is 141.
1, 3, 5, 15, 47, 141, 235, 705.