First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
Add the two numbers and divide that by two.
49- 16 = 33. 49is 7 squared, and 16 is 4 squared.
You divide decimals like you normally would divide two numbers. Just make sure your decimals get in the right spot and your good! :)
1 and 36 is one of two possible pairs -> so the squared numbers are 12 and 62
The two numbers in question are 1 and 9. 1 is equal to 1 squared, and 9 is equal to 3 squared.
7 squared and 3 squared. 49 - 9 = 40
There are no two whole numbers which when squared sum to 62. There are infinitely may pairs of irrational numbers that when squared sum to 62, eg 1 and √61, 2 and √58
you square the hypotenuse and find two numbers when squared and then added together equal the hypotenuse squared then the numbers before they were squared are the two legs
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
You have to add those two numbers then divide them by 2. The reason you divide by 2 is because they're two numbers.
2 squared = 4 8 squared = 64 2 squared + 8 squared = 4 + 64 = 68 8 squared - 2 squared = 6 squared = 36 The product of 8 x 2 = 16.
Two.Two.Two.Two.
It depends on what the 4000 square numbers are.
divide the two numbers then divide
Add the two numbers and divide that by two.
When you divide two numbers the answer is the quotient.