It is a square because its diagonals are equal in length and they bisect each other at right angles which is 90 degrees
The diagonals of a rhombus are not equal in length but they meet at right angles.
A square.
In general, no, they are not.
square
It can be :- 1- a parallelogram 2- Square if diagonals are perpendicular and congruent 3- Rectangle if diagonals are congruent 4- Rhombus if diagonals are perpendicular
It could be a square, but consider the following congruent & perpendicular 'diagonals of a quadrilateral (you will have to connect the endpoints of the diagonals, yourself, as it cannot be drawn in text): . _|___ . | . | . | If the two diagonals, also bisect each other, then it's a square, otherwise it is not.
If the diagonals are congruent and are perpendicular bisectors of each other then the parallelogram is a square. If the diagonals are not congruent but are perpendicular bisectors of each other then the figure would be a rhombus.
A square.
The quadrilateral that must have diagonals that are congruent and perpendicular is the square. This is because its diagonals form a right angle at its center.
In general, no, they are not.
square
It can be :- 1- a parallelogram 2- Square if diagonals are perpendicular and congruent 3- Rectangle if diagonals are congruent 4- Rhombus if diagonals are perpendicular
square
It could be a square, but consider the following congruent & perpendicular 'diagonals of a quadrilateral (you will have to connect the endpoints of the diagonals, yourself, as it cannot be drawn in text): . _|___ . | . | . | If the two diagonals, also bisect each other, then it's a square, otherwise it is not.
Rectangle: A quadrilateral with 4 right angles, diagonals congruent/bisecting, and opposite sides congruent, BUT ADJACENT SIDES ARE NOT CONGRUENT. Rhobus: A quadrilateral with opposite congruent angles, but adjacent angles are Not congruent, perpendicular bisecting diagonals and 4 congruent sides. Square: A quadrilateral that is a rectangle and a square with 4 right angles, diagonals congruet/bisecting that ar perpendicular, and opposites sides congruent.
Not necessarily - the diagonals of a rhombus bisect each other (they are perpendicular bisectors of each other), but are not equal.
True, the diagonals of a rhombus are perpendicular bisectors of one another.
No, they are just bisectors. The angle between them is not (usually) the 90o required to be perpendicular.