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Solving for 3 variables can be done in many different ways. Such a problem is commonly referred to as a "system of equations" or "simultaneous equations". A few different methods exist for solving these systems: substitution, elimination, and matrix manipulation.

Substitution: In this method each variable is written in terms of a different variable and substituted into an equation until just 1 variable remains.

[1] 2a+b+c=7 ==>a=(7-b-c)/2

[2] -2a+5b-2c=2 ==>b=(2+2c+2a)/5

[3] a+10b+c=24 ==>c=24-10b-a

Substituting [3] into [1]: a=(7-b-(24-10b-a))/2 ==> a=(9b-17)

Substituting [3] into [2]: b=(2+2(24-10b-a)+2a)/5 ==> b=(-20b+50)/5 ==> b=2

Substituting b=2 into a=(9b-17) ==> a=(9*2-17) ==> a=1

Substituting a=1 and b=2 into equation 3: 1+10*2+c=24 ==> c=3

Solution: a=1, b=2, c=3

Elimination: Add a factor of one equation to a different one to eliminate a variable

[1] 2a+b+c=7

[2] -2a+5b-2c=2

[3] a+10b+c=24

[1]+[2] ==> 6b-c=9

2*[3]+[2] ==> 25b=50 ==>b=2

Then we can substitute b=2 into 6b+c=9 to solve for c: 6*2-c=9 ==> c=3

Substituting b=2 and c=3 into [1] ==> 2a+2+3=7 ==> a=1

Matrix Manipulation (Cramer's Law): While this method seems complex, it is often easier, especially with large systems. It is also the most procedural method.

[1] 2a+b+c=7

[2] -2a+5b-2c=2

[3] a+10b+c=24

Step 1. Find the determinants* of the coefficient matrix

A=

|2 1 1|

|-2 5 -2|

|1 10 1|

[4] det(A)=2*(5+20)-1*(-2+2)+1*(-20-5)=25

Step 2. Replace the column of the variable you are trying to find in the coefficient matrix with the constants (in this case: replace 2, -2,1 with 7,2, 24) and find the determinant. We will just solve for a as an example.

Solving for a:

A'=

|7 1 1 |

|2 5 - 2 |

|24 10 1 |

[5] det(A')=7*(5+20)-1*(2+48)+1*(20-120)=25

Step 3. Divide the coefficient matrix of which a column was replaced by the coefficient matrix:

a=[5]/[4]=25/25=1

Repeat steps 2 and 3 for each variable

*There are many methods of finding a determinant, I used the expansion by minors technique

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How do you solve three nonlinear equations in three parameters?

There isn't a universal way to do this, just like there isn't a universal way to solve nonlinear equations in one variable. A good place to start, however, would be to attempt to solve an equation for one of the variables, in terms of the other two. If you substitute that into the other equations, you will then have a system of two equations in two variables. Do this again, and you'll have a single variable equation that you'll hopefully know how to solve.


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What is definning variables?

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Related Questions

How do you solve 3 dimensional equations?

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-w plus 2x plus 4y equals?

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How do you solve three nonlinear equations in three parameters?

There isn't a universal way to do this, just like there isn't a universal way to solve nonlinear equations in one variable. A good place to start, however, would be to attempt to solve an equation for one of the variables, in terms of the other two. If you substitute that into the other equations, you will then have a system of two equations in two variables. Do this again, and you'll have a single variable equation that you'll hopefully know how to solve.


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