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The length of a rectangle is two times its width. If the perimeter of the rectangle is 48 what is its area?
length = 2 x width Perimeter = 2 x (length x width) =2 x (2 x width + width) = 2 x (3 x width) = 6 x width → 6 x width = 48 units → width = 48 units ÷ 6 = 8 units → length = 2 x width = 2 x 8 units = 16 units Ares = length x width = 16 units x 8 units = 128 square units
What is shape if perimeter is 16 and area is 15?
This is a rectangle with length 5 units and width 3 units. The area = length x width = 5 x 3 = 15 sq units. The perimeter = 2 x (length + width) = 2 x 8 = 16 units.
What is the length of a rectangle when the perimeter is 60 and the length is twice the width?
The length is 20 units and the width is 10 units
The length and width of a rectangle are consecutive even integers The area of the rectangle is 80 square units What are the length and width of the rectangle?
10 units and 8 units respectively
What is the Length and width of a rectangle if the diagonal is 9?
length = 7.2 units and width = 5.4 units Solved by means of Pythagoras' theorem.
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