Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
Perimeter = 15+15+35+35 = 100 cm
Assuming that the length of a rectangle is greater than its breadth, any value L such that 15 ≤ L < 30 cm will do. Then breadth, B = 30 - L cm.
It is: 2+15+2+15 = 34cm
44
15
Perimeter of rectangle: 2*(20+15) = 70m
The area cannot be 15 feet since that is a measure of length, not area. In any case, information about the area cannot determine the perimeter; it can only put a lower limit on it. The perimeter can be anyhting from 15.49193 ft upwards. Consider the following rectangles, all with area = 15 square feet: a sqrt(15)*sqrt(15) rectangle will have a perimeter of 4*sqrt(15) = 15.49193 ft (approx). 1ft*15ft rectangle will have a perimeter of 32 feet 0.1ft*150ft rectangle: perimeter = 300.2 feet 0.01ft*1500ft rectangle: perimeter = 3000.02 ft 0.001ft*15000ft rectangle: perimeter = 30000.002 ft by now you should see that there is no upper limit to the perimeter.
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
Perimeter is the sum of the measures of the side lengths. A rectangle with length 15 and width 7 has two sides that measure 15 and two that measure 7. So 7 + 7 + 15 + 15 = 44 is the perimeter.
Perimeter = 15+15+35+35 = 100 cm
Assuming that the length of a rectangle is greater than its breadth, any value L such that 15 ≤ L < 30 cm will do. Then breadth, B = 30 - L cm.
It is not. The perimeter of a 1 cm square is 4 cm. The perimeter of a 5 km * 15 km rectangle is 4000000 cm: a million times as large!
2+2+15+15=34cm
The perimeter of a rectangle is given by:P = 2l + 2w, where P is the perimeter of the rectangle, l is the length of the rectangle, and w is the width of the rectangle.P = 2(15) + 2(10) = 50 meters.
It is: 2+15+2+15 = 34cm
The dimensions of the rectangle are 2 units and 15 units