The perimeter of a rectangle is calculated by adding up the lengths of all its sides. In this case, the length is 15 centimeters and the width is 10 centimeters. To find the perimeter, you would add up all four sides: 15 cm + 10 cm + 15 cm + 10 cm = 50 cm. Therefore, the perimeter of the rectangle is 50 centimeters.
56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
1.10*X=402. Divide each side by 10:X=4 centimeters3. Check your answer 10*4=40The width of the rectangle is 4 centimeters
6x4 has a perimeter of 2*(6+4) = 2*10 = 20 cm 6.5x2 has a perimeter of 2*(6.5+2) = 2*8.5 = 17 cm So the first has the larger perimeter.
For a start at this question, find out how wide this rectangle must be. area (250) = length (25) x width (???) The area of a rectangle is its length times its width. We should divide the area by the length (25) to get the width. The answer is 10. Then we know that each long side is 25 and each short side is 10. We know that in a rectangle, the long sides are the same length and the short sides are the same width. In order to get the perimeter, we add 25 and 25 and 10 and 10. We get 70. So the perimeter is 70.
Length 17 cm. Width 10 cm.
width:10,length;17 17*2+10*2=54
Let the width be x: 2(length+width) = perimeter 2(20+x) = 50 40+2x = 50 2x = 50 -40 2x = 10 x = 5 centimeters Check: 5+5+20+20 = 50 centimeters
28 cm
The perimeter of a rectangle with length of 10 miles and width of 5 miles is 30 miles.
56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
One rectangle that has a perimeter of 30 has a length of 5 and a width of 10.
It is 10 feet
breadth = 4x - 10 ie length + breadth = 5x - 10. Perimeter is double this figure ie 10x - 20 or 10(x - 2)
The perimeter of a rectangle is given by:P = 2l + 2w, where P is the perimeter of the rectangle, l is the length of the rectangle, and w is the width of the rectangle.P = 2(15) + 2(10) = 50 meters.
(10+10)+(5+5)=30cm
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.