x>|7| + |8|
x2 = 16take the root square for both sides the result will be :X = +4 or -4
Not unless you have an infinite amount of time as there are an infinite amount of numbers that are solutions to an inequality.
Infinite.
iF THE QUESTION IS WRITTEN LIKE THIS: WHAT IS THE VALUE IN r IN THE INEQUALITY 5>r=3. THEN THE BEST POSSIBLE ANSWER WOULD BE...D) R<8
Find the possible values of r in the inequality 5 > r - 3.Answer: r < 8
Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.
x>|7| + |8|
x ≤ -sqrt(11) or x ≥ sqrt(11)
x2 = 16take the root square for both sides the result will be :X = +4 or -4
2
Not unless you have an infinite amount of time as there are an infinite amount of numbers that are solutions to an inequality.
a solution of inequality
x - 3 is not an inequality.
Which region you shade depends on whether you are required to shade the possible values or the values that need t be rejected. In 2 or more dimensions, you would normally shade the regions to be rejected - values that are not solutions. With a set of inequalities, this will result in an unshaded region (if any) any point of which will satisfy all the equations.If the inequality is written in the form x < N where N is some given value, then the possible solutions are to the left of N and the rejected values are to the right. Whether the value N, itself, is shaded or not depends on whether the inequality is strict or not.
There are many possible answers but the simplest is |x + 2| = 8
It does not have any solutions! 14.8 is a number, not an equation, inequality or question and so has no solutions.