There is insufficient information for us to even begin to understand this question. Please edit the question to include more context or relevant information. There is no inequality in the question.
x>|7| + |8|
x2 = 16take the root square for both sides the result will be :X = +4 or -4
Not unless you have an infinite amount of time as there are an infinite amount of numbers that are solutions to an inequality.
To solve the inequality (8x^2 - x < 0), we first factor it as (x(8x - 1) < 0). The critical points are (x = 0) and (x = \frac{1}{8}). Analyzing the sign of the product in the intervals determined by these points, we find that the inequality holds for (0 < x < \frac{1}{8}). Since there are no integer values of (x) in this interval, the number of different integer values of (x) that satisfy the inequality is zero.
The graph of the inequality ( x < 4.5 ) is a vertical line drawn at ( x = 4.5 ), with a dashed line indicating that the line itself is not included in the solution set. The region to the left of this line represents all the values of ( x ) that satisfy the inequality. Therefore, the area shaded will extend infinitely to the left, indicating that all ( x ) values less than 4.5 are solutions.
Find the possible values of r in the inequality 5 > r - 3.Answer: r < 8
Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.
x>|7| + |8|
The shaded region above or below the line in the graph of a linear inequality is called the solution region. This region represents all the possible values that satisfy the inequality. Points within the shaded region are solutions to the inequality, while points outside the shaded region are not solutions.
x2 = 16take the root square for both sides the result will be :X = +4 or -4
x ≤ -sqrt(11) or x ≥ sqrt(11)
2
a solution of inequality
Not unless you have an infinite amount of time as there are an infinite amount of numbers that are solutions to an inequality.
x - 3 is not an inequality.
There are many possible answers but the simplest is |x + 2| = 8
Which region you shade depends on whether you are required to shade the possible values or the values that need t be rejected. In 2 or more dimensions, you would normally shade the regions to be rejected - values that are not solutions. With a set of inequalities, this will result in an unshaded region (if any) any point of which will satisfy all the equations.If the inequality is written in the form x < N where N is some given value, then the possible solutions are to the left of N and the rejected values are to the right. Whether the value N, itself, is shaded or not depends on whether the inequality is strict or not.