It was a World War II Pillbox (gun housing) that fell into the sea a long time ago.
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The amount of water displaced by the block is the volume of the block. so (volume of water with block in it)-(original volume of water)= volume of block
The weight of water displaced by the floating block of wood is exactly equal to the weight of the ENTIRE block of wood, regardless of how much of the wood is above the water level.
0 oC is freezing point of water. So while you can pour at this temperature you need to take some precautions.
Using the rough rule-of-thumb: 1 liter of water = 1 kg.-- The block sinks until it has displaced 720 liters of water. At that point,the mass of the displaced water has the same weight as the mass of theblock has, and the block sinks no further.-- The block still has 280 liters of its volume above water. If that were submerged,another 280 kg of water would be displaced.-- The additional 280 kg of water would weigh (280 x 9.8) = 2,744 newtons (617.3 pounds).That much additional buoyant force would fight the effort to submerge the block.It takes an additional 2,744 newtons (617.3 pounds) to keep the block under water.
To do this you would need to know the density of unmixed concrete (i.e what is the weight of concrete per unit of volume), and the ratio of concrete to water required. (I assume you mean 1m^3 of mixed concrete (with water) to kg, rather than the unmixed concrete powder). With these bits of information the conversion is relatively simple, however I don't know where to find this information from. Alternatively, just the density of mixed concrete would suffice.