Not all paint covers the same area.You need to find out what it claims to cover,then calculate the surface area by multiplying the height and width of the individual walls.
length 14cm, width 2cm This is worked out by finding the following equations: perimeter = 16 x width length = width + 12 Then working out 16 x width = 2 x (width + 12) + 2 x width -> 14 x width = 2 x (width + 12) -> 14 x width = 2 x width + 24 -> 12 x width = 24 -> width = 2cm Since lendth = width + 12, length = 14cm
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
261.25 square feet on the floor. 261.25 square feet on the ceiling. (65.5 x height of the room) square feet on the four walls.
AREA = LENGTH x WIDTH LENGTH = 2 X WIDTH AREA = 2 x WIDTH X WIDTH = 900 900/2 = WIDTH X WIDTH 450 = WIDTH X WIDTH = WIDTH SQUARED WIDTH = SQUARE ROOT (450) = 21.21 FEET LENGTH = 42.42 FEET
Brickwork in house walls has a width of 3-5/8 inches.
Compare to the width of an atom, yes
Compare to the width of an atom, yes
according to http://www.soundvision.com/info/hajj/kaba.asp the width of the kabaa's walls are 1 meter wide
If you're trying to find the total area of 4 walls:(Length of wall 1 x width of wall 1) + (Length of wall 2 x width of wall 2) + (Length of wall 3 x width of wall 3) + (Length of wall 4 x width of wall 4) = total areaThe area enclosed by four walls if they form a rectangle or square is length x width.The area of a rectangular wall is hw where h is the height and w is the width. In an ordinary rectangular room, there are 4 walls and opposite walls are equal, and the heights are all equal, formula is A = hw1 + hw2 + hw1 + hw2 = 2hw1 + 2hw2 = 2h ( w1 + w2) , where the floor is w1 by w2.If the floor is square, w1 = w2 and the formula simplifies to A = 4hw1.
It depends on the thickness and width of the footings and the thickness and height of the foundation walls.
It depends upon what you are calling height and what the thing is, what the area is, that is being measured. If you have a three dimensional shape and are measuring the area of the base which has dimensions length and width, then the height is irrelevant. If you have a three dimensional shape and are measuring the area of the back then the area will be calculated as width times height and you need to consider the height If you have a room and are considering how much paint you need to buy to paint the walls, then you are calculating the surface area of the walls and will need to consider the height as you will have 2 walls length × height and 2 walls width × height. If you are considering the surface area of a cuboid, then the height will also need to be considered as you will have 2 faces each of width × length, length × height, height × width.
Presuming that a room is a rectangular prism, with a solid floor, ceiling and walls, we have 6 rectangles which make up the surface area of the room. Since rectangular prism's are symmetrical, each side of the prism is identical to it's opposing side. Or in other words, if we say that the length of the floor is 'a', and the width of the floor is 'b', then the area of the floor is a * b, and the area of the ceiling is a * b. Thus we have that the surface area of the floor and ceiling combined is: 2 * a * b Next, notice that all 4 walls have the same height. Also notice that 2 of the walls run along the length of the floor, and the other 2 walls run along the width of the floor. If we say that the height of the walls is 'c', then we have that the surface area of the walls that run along the length of the floor is: 2 * a * c and the surface area of the walls that run along the width of the floor is: 2 * b * c If we add all of these together, then we have that the total surface area of the room is: 2 * a * b + 2 * a * c + 2 * b * c = 2 * (a*b + a*c + b*c)
{| class="tdefault" | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |} ---- === === === === === === === ===
There were three Nehemiah's in the Bible. The most notable one was the prophet Nehemiah who served the Persian King Artaxerxes. This Nehemiah was the Son of Hacaliah, and brother of Hanani. For a full discussion on Nehemiah, see the attached link:
Rims were 14X5, and the tires were about 5.5 inches wide. I think the SS might have had a 6 inch tire, with white walls.
The thickness of a wall would depend on the construction. Modern houses would probably have exterior walls not much thicker than a brick. As a rule the older the house (and colder the climate) the thicker the walls. I've seen exterior walls 4 feet thick in medieval welsh cottages for example.