Presuming that a room is a rectangular prism, with a solid floor, ceiling and walls, we have 6 rectangles which make up the surface area of the room.
Since rectangular prism's are symmetrical, each side of the prism is identical to it's opposing side. Or in other words, if we say that the length of the floor is 'a', and the width of the floor is 'b', then the area of the floor is a * b, and the area of the ceiling is a * b. Thus we have that the surface area of the floor and ceiling combined is:
2 * a * b
Next, notice that all 4 walls have the same height. Also notice that 2 of the walls run along the length of the floor, and the other 2 walls run along the width of the floor. If we say that the height of the walls is 'c', then we have that the surface area of the walls that run along the length of the floor is:
2 * a * c
and the surface area of the walls that run along the width of the floor is:
2 * b * c
If we add all of these together, then we have that the total surface area of the room is:
2 * a * b + 2 * a * c + 2 * b * c
=
2 * (a*b + a*c + b*c)
Let its dimensions be a, b and c:- Surface area of the cuboid: 2*(a*b)+2*(b*c)+2*(a*c) in square units
The answer should be: (2*a*b)+(2*b*c)+(2*c*a)
If the dimensions of a cuboid are a, b and c (a=1,b=1,c=20), then its surface area is:2*a*b + 2*b*c + 2*a*c, which is, in your case:2*1*2 + 2*2*20 + 2*1*20 = 4+80+40 = 124So, the answer is 124.
If the bases have sides of length a, b and c units and the length of the prism is d units thenlateral area = (a+b+c)*darea of base = sqrt{s*(s-a)*(s-b*(s-c)} where s = (a+b+c)/2Then total surface area = lateral area + 2*area of base.
b/c in room temperature, it's a gas
If you mean on a raport card, yes, A is best, then a B, C is just average and room for improvement. No one wants to get a D!!
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For a box with equal dimensions on all sides, the surface area, S, is calculated as follows: S = 6*a^2 where a is the length of the side of the box For a box with different dimensions on the sides, the surface area, S, is calculated as follows: S = 2*a*b + 2*a*c + 2*b*c where a, b, c are the lengths of the different sides of the box
a b c a c a d a c c c a c b b b a a c b b b a c c b
No. In any triangle on a plane surface, each exterior angle is equal to the sum of the other two interior angles. Suppose A,B and C are the interior angles and a b and c the corresponding exterior angles. Then a < 90 implies that B + C < 90 and b< 90 implies that A + C < 90 This gives B+C+A+C < 180 so that A+B+C < 180 which contradicts a property of triangles.
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a b c c c c b a g g a b g a b c c c c b a g b a a b c c c c b a g g a b a b c d b c e c b a b a g g