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What is xy-2 when x equals 5 and y equals 4?
18
In inverse proportion x equals 2 and y equals 36 but what will y be when x equals 4?
Inverse proportion implies xy = c where c is the constant of [inverse] proportionality. x = 2 and y = 36 implies xy = 72 = c So the relationship is xy = 72 Then, if x = 4, y = 72/x = 72/4 = 18
What are the coordinated when x-2y equals 8 intersects with xy equals 24?
The coordinates are: (-4, -6) and (12, 2)
2 to the power of 7 multiplied by 2 to the power of 2 equals?
According to the laws of exponents, xy times xz = xy+z. Therefore, 27 x 22 = 2(7+2) = 29 = 512.
How many asymptotes does a hyperbola have?
A hyperbola has 2 asymptotes.www.2dcurves.com/conicsection/​conicsectionh.html
Is an ellipse is similar to a circle?
How is a circle similar to an ellipse?The eccentricity of a circle is zero.The eccentricity of an ellipse which is not a circle is greater than 0, but less than 1.The eccentricity of a parabola is 1The eccentricity of a hyperbola is greater than 1Definition of eccentrica person with an unusual or odd personalitybizarre: conspicuously or grossly unconventional or unusual;.A circle is the perfect shape, all point are equidistant from the center. I believe we could agree that the circle has no eccentricity!!The eccentricity of a circle is zero..On the other hand the ellipse has points that 2 centers, a little eccentric. The farther the 2 points are apart the more eccentric the ellipse is.If you take any point on the ellipse, the sum of the distances to the focus points is constant. The eccentricity of an ellipse which is not a circle is greater than 0, but less than 1.If you stretch the ellipse too far it will break open and be a parabola. The eccentricity of a Parabolais 1. The parabola just keeps spreading out in both directions. At least it is still symmetrical. It has bottom (vertex),but the top just keeps spreading out.The eccentricity of a parabola is 1The eccentricity of a hyperbola is greater than 1The points on a hyperbola get close to the x-axis and y-axis, but never touch either axis.The eccentricity of a circle is zero. Think about the equation of each of these shapes Circle x^2 + y^2 = r ^2 How beautiful y^2 = r ^2 - x^2The eccentricity of an ellipse which is not a circle is greater than 0, but less than 1.Ellipse Equation(x^2 ÷ a^2) + (y^2 ÷ b^2) = 1Getting more eccentric with those a^2's an b^2'sParabola EquationY = k * x^2Now poor y is not squared The eccentricity of a parabola is 1Hyperbola Equationx * y = constanty = constant ÷ xNow poor x is in the denominator The eccentricity of a hyperbola is greater than 1
What is xy-2 when x equals 5 and y equals 4?
18
Implicit differentiation of xy plus x equals 2?
It equals y+1
The eccentricity of hyperbola 3x power 2 minus y power2 plus 4i The answer is 2 how?
There is no equation in the question: only an expression. Also, is there meant to be an i after the 4? Please edit the question to include more context or relevant information.
In inverse proportion x equals 2 and y equals 36 but what will y be when x equals 4?
Inverse proportion implies xy = c where c is the constant of [inverse] proportionality. x = 2 and y = 36 implies xy = 72 = c So the relationship is xy = 72 Then, if x = 4, y = 72/x = 72/4 = 18
What are the coordinated when x-2y equals 8 intersects with xy equals 24?
The coordinates are: (-4, -6) and (12, 2)
How many foci does the graph of a hyperbola have?
Two foci's are found on a hyperbola graph.
2 to the power of 7 multiplied by 2 to the power of 2 equals?
According to the laws of exponents, xy times xz = xy+z. Therefore, 27 x 22 = 2(7+2) = 29 = 512.
What are the points of intersection of the straight line x -2y equals 8 with the curve of xy equals 24?
We solved the first equation for 'x': [ x = 2y + 8 ].Then we substituted it for 'x' in the second equation and rearranged: [ y2 + 4y - 12 = 0 ].Solutions of this quadratic equation are: y = 2 and -6. From which x = 12 and -4 .So the straight line intersects the hyperbola at (-4, -6) and at (12, 2) .
How many asymptotes does a hyperbola have?
A hyperbola has 2 asymptotes.www.2dcurves.com/conicsection/​conicsectionh.html
How do you find the asympototes of the hyperbola 16y2 - 4x2-64 equals 0?
Y =sqrt(4x^2 +64/16) I would, after factoring, say +/- 2; horizontally
2x2 plus y2 - xy equals 21?
if you meant 2x²+y²-xy=21x=(±sqrt(-7 y^2+168)+y)/4y=(±sqrt(-7 x^2+84)+x)/2
