Use Pythagoras' theorem:
82+52 = 89 and the square root of this is 9.433981132 cm
5 x 10 = 50cm2
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
Perimeter of rectangle: 5+3+5+3 = 16cm
5*3 = 15 square cm
5cm x 2cm=10cm²A=10cm²
5 x 10 = 50cm2
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
Perimeter of rectangle: 5+3+5+3 = 16cm
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
5*3 = 15 square cm
the perimeter of a rectangle with two 5cm squares will be 30cm
It has 2 sides of 5 cm and 2 sides of 6 cm so the perimeter is 22 cm
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
Area of a rectangle= Length * width Length= 5cm Width= 1cm Area=5cm *1cm =5cm2
5cm x 2cm=10cm²A=10cm²
To find the area of a rectangle, you multiply its length by its width. In this case, the length is 7cm and the width is 5cm. So, the area of the rectangle is 7cm x 5cm = 35 square centimeters.
12.5cm