Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal.
Here, a = 5 [cm] and b = 10 [cm]
So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored)
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Pythagoras! If AB = 100m and BC = 75cm then AC = sqrt (10000 + 5625) = 125
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
Two equal size right angle triangles.
Arthur Pythagoras: Diagonal = sqrt (square of side 1 + square of side 2) In your case D = sqrt (2 x 2500) = 70.71cm Addendum: If it is a square, as is your case, multiply the length of one side by the square root of 2: 1.4142 * 50.00 cm = 70.71 cm. (Arthur?)
When you draw a diagonal in a rectangle or a parallelogram, it divides the shape into two congruent triangles, meaning both triangles are the same size and shape. In contrast, drawing a diagonal in a trapezoid results in two triangles that can differ in size and shape, as the bases of the trapezoid are unequal. Thus, different size and shape triangles form only in the trapezoid.
d = 11.5 inches.
Pythagoras! If AB = 100m and BC = 75cm then AC = sqrt (10000 + 5625) = 125
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
Two equal size right angle triangles.
10cm
the size is 10cm
Arthur Pythagoras: Diagonal = sqrt (square of side 1 + square of side 2) In your case D = sqrt (2 x 2500) = 70.71cm Addendum: If it is a square, as is your case, multiply the length of one side by the square root of 2: 1.4142 * 50.00 cm = 70.71 cm. (Arthur?)
When you draw a diagonal in a rectangle or a parallelogram, it divides the shape into two congruent triangles, meaning both triangles are the same size and shape. In contrast, drawing a diagonal in a trapezoid results in two triangles that can differ in size and shape, as the bases of the trapezoid are unequal. Thus, different size and shape triangles form only in the trapezoid.
squares or more rectangles depending on the size of the rectangle to begin with and how you cut it.
13 cm Solved with the help of the quadratic formula and Pythagoras' theorem.
10cm to 15cm
10cm