Wiki User
∙ 11y agoA regular pentagon in which the base has been stretched out (or squashed) equally in both directions.
Wiki User
∙ 11y agoIf all the sides and angles of a pentagon were equal, you would be able to put a mirror through the centre, and have the reflection be equal to the original image. This means that it would have reflective symmetry. If a pentagon does not have reflective symmetry, then it's angles and side lengths cannot all be the same. Thus, it is an irregular pentagon.
In general, a square. A square always has 4 lines of symmetry. A pentagon need not have any. Only a regular pentagon can have 5 lines of symmetry. But if you created pentagons from sides with random lengths then, assuming the pentagons existed, only a tiny fraction would be regular: most pentagons would have no axes of symmetry.
Yes, but it would have to be an irregular one.
The Pentagon has 5 lines of symmetry quite simply, actually. See, say you made one line straight through the pentagon at every vertex, right? Well, once you do that, you have 3 lines of symmetry in total, right? Now, say you make another 2 lines of symmetry, this time right through the center of each side. In total, this would make 5.
To have no symmetry the four sides would all have different lengths, and each angle would also be different. The figure would not look like a square or a rectangle, but would instead be an irregular 4-sided polygon.
If all the sides and angles of a pentagon were equal, you would be able to put a mirror through the centre, and have the reflection be equal to the original image. This means that it would have reflective symmetry. If a pentagon does not have reflective symmetry, then it's angles and side lengths cannot all be the same. Thus, it is an irregular pentagon.
It would then be classed as an irregular 5 sided pentagon.
In general, a square. A square always has 4 lines of symmetry. A pentagon need not have any. Only a regular pentagon can have 5 lines of symmetry. But if you created pentagons from sides with random lengths then, assuming the pentagons existed, only a tiny fraction would be regular: most pentagons would have no axes of symmetry.
An irregular 5 sided pentagon that looks like a hut would fit the given description.
Yes, but it would have to be an irregular one.
An irregular 5 sided pentagon that looks like a hut would fit the given description.
The Pentagon has 5 lines of symmetry quite simply, actually. See, say you made one line straight through the pentagon at every vertex, right? Well, once you do that, you have 3 lines of symmetry in total, right? Now, say you make another 2 lines of symmetry, this time right through the center of each side. In total, this would make 5.
Any polygon with an even number of sides can have two lines of symmetry, but it would have to be irregular.
An irregular pentagon would have the same number of degrees (collective angle degrees) as a regular pentagon. (But, honestly, I don't know the number of degrees in a pentagon right off the top of my head.) Just like how all triangles have a total of 180 degrees and all quadrilaterals have a total of 360 degrees.
One which has sides of differing lengths, when their REGULAR form can be made from sides of all the same length. For example, a distorted regular pentagon would be irregular.
Yes. It is impossible for a regular pentagon to have two right angles, but quite possible with an irregular pentagon in which the angles are not all equal. The resulting shape looks like how a child would draw a house.
I would say a convex irregular pentagon. Convex as any line drawn between two points can be contained inside the shape, Pentagon since it is 5 sided, but irregular because if you look at it topographically, it looks like the side of a house. As opposed to the true pentagon whose east-west walls are angled out and the sum of the angles is 540 degrees.