0
Add your answer:
Earn +20 pts
What is the area of a triangular face of a square pyramid with a base area of 16 cm?
You did not give the height of the pyramid and 16 cm is not an area, but the area of the face would be one half the face height of the side of the pyramid times the length of the base side.
If a particular right square based pyramid has a volume of 63690 cubic meters and a height of thirty meters What is the number of meters in the length of the lateral height segment AB of a pyramid?
The formula for the volume of a pyramid such as you described would be: V = 1/3Ah where A is the area of the base (a square in this case) and h is the height of the pyramid. You know the volume and the height, so you can plug them into that formula to solve for A, the area of the square base: 63690 = 1/3A(30). A = 6369 square meters. Knowing the area of the square, and the fact that the formula for the area of a square is A = s2 where s is the length of a side, you can find the length of s by taking the square root of 6369. s = about 79.8 meters. The next steps will require some thinking about what that pyramid looks like and what the length of a lateral height segment would represent. Drawing a diagram often helps. If I understand correctly what you mean by "lateral height segment" of the pyramid, meaning the length of the segment from the center of a side at the bottom to the vertex at the top, that length would represent the hypotenuse of a right triangle whose legs are 30 meters (the inside height of the pyramid) and about 39.9 meters (half the length of a side, in other words the distance from the point at the center of the base to the center of the side). You can use the Pythagorean theorem to find that length: c2 = a2 + b2 c2 = 302 + 39.92 c2 = 900 + 1592 c2 = 2492 c = 49.9 meters (approximately)
What is the volume of a ramp?
I think since a ramp is a rectangular pyramid you would use the formula Volume= one-third times length times width times height
Is the height of a pyramid visible on its net?
No. You would have to use Pythagoras's theorem.
What is the surface area of the square pyramid shown if the base has a side length of 8 inches and l 15 inches?
To calculate the surface area of a square pyramid, you need to find the area of the base (which is a square) and the area of the four triangular faces. The formula for the surface area of a square pyramid is SA = s^2 + 2sl, where s is the side length of the base and l is the slant height. In this case, with a base side length of 8 inches and a slant height of 15 inches, the surface area would be SA = 8^2 + 2(8)(15) = 64 + 240 = 304 square inches.
What is the area of a triangular face of a square pyramid with a base area of 16 cm?
You did not give the height of the pyramid and 16 cm is not an area, but the area of the face would be one half the face height of the side of the pyramid times the length of the base side.
How do you find the slant height of a pyramid with a rectangular base?
If you make a line from the top of the pyramid to the center of the base, you have the height of the pyramid. This meets at the midsegment of a line going across the base. Since the height of a pyramid is perpendicular with the base, get this: the height, a line of 1/2 the length of the base, and the slant height form a right triangle. So, you can use the Pythagorean Theorem! For example, if the base length is 6 and the height of the pyramid is 4, then you can plug them into the Pythagorean Theorem (a squared + b squared = c squared, a and b being the legs of a right triangle and c being the hypotenuse). 1/2 the length of the base would be 6 divided by 2=3. 3 squared + 4 squared = slant height squared. 9+16=slant height squared. 25= slant height squared. Slant height=5 units. You're welcome!
The slant height of a pyramid is 46 ft The base is a square with a side length of 24 ft What is the height of the pyramid Round your answer to the nearest tenth?
If there is a picture, it would be very useful, because the height and slant height are two sides of a right triangle. A good picture would show that the bottom side of this triangle is half the side length of the square. This is a leg of the right triangle: A=12' The hypotenuse of the triangle is the slant height: C=46' The "unknown" height is the other leg of the right triangle: B=? The pythagorean theorem A2+B2=C2 gives 144sqft+B2=2116sqft Solving for B gives B=44.4' Therefore, the height of the pyramid is 44.4 feet.
If a particular right square based pyramid has a volume of 63690 cubic meters and a height of thirty meters What is the number of meters in the length of the lateral height segment AB of a pyramid?
The formula for the volume of a pyramid such as you described would be: V = 1/3Ah where A is the area of the base (a square in this case) and h is the height of the pyramid. You know the volume and the height, so you can plug them into that formula to solve for A, the area of the square base: 63690 = 1/3A(30). A = 6369 square meters. Knowing the area of the square, and the fact that the formula for the area of a square is A = s2 where s is the length of a side, you can find the length of s by taking the square root of 6369. s = about 79.8 meters. The next steps will require some thinking about what that pyramid looks like and what the length of a lateral height segment would represent. Drawing a diagram often helps. If I understand correctly what you mean by "lateral height segment" of the pyramid, meaning the length of the segment from the center of a side at the bottom to the vertex at the top, that length would represent the hypotenuse of a right triangle whose legs are 30 meters (the inside height of the pyramid) and about 39.9 meters (half the length of a side, in other words the distance from the point at the center of the base to the center of the side). You can use the Pythagorean theorem to find that length: c2 = a2 + b2 c2 = 302 + 39.92 c2 = 900 + 1592 c2 = 2492 c = 49.9 meters (approximately)
What is the volume of a ramp?
I think since a ramp is a rectangular pyramid you would use the formula Volume= one-third times length times width times height
A square pyramid has a height of 18cm and base that measures 12cm on each side explain whether tripling the height would triple the volume of the pyramid?
Well, isn't that a delightful question! If you triple the height of the square pyramid, the volume will indeed be tripled. You see, when you triple the height, you are essentially tripling the number of layers of the pyramid, which results in tripling the volume. Just imagine those layers of paint on a canvas, each one adding to the beauty of the final masterpiece!
How do you find the width of a cube when you have the length and height of it?
The width height and length would all be the same
A pyramid has a square base with sides 8 and a slant height of 5?
This pyramid would have a perpendicular height of 3, a volume of 64 units3 and a slant edge of 6.403
Is the height of a pyramid visible on its net?
No. You would have to use Pythagoras's theorem.
A the base of a pyramid is regular quadrilateral with a side length of the numbers 30 feet and a height of 27 feet How many cubic yards of cement would you need to fill the pyramid with cement?
There is no possible way to find this. However, one can find the volume of a pyramid by simply using this formula: V=bh1/3
If a pyramid has a lenght and width of 14 meters and a slant height of 24 meters and a height of 22.96 meters what would the volume be?
The volume would be 1,500 m3
How do you calculate the dimensions of a square pyramid with a surface area of 260cm2?
There is not enough information given to solve the problem - explanation follows. A square pyramid can be thought of as four triangles connected by a square bottom. The area of each triangle = .5 * height(H) * length(L) The area of the square = L2 Surface area of the square pyramid = L2 + 2HL = 260 Unfortunately, without having a relationship between Length and Height, this equation is unsolvable (infinite number of solutions). For example, if we knew that the Height was 8 cm, then the formula would be factor-able: L2 + 16L - 260 = 0 (L+26)(L-10)=0 L=10 cm It is also solvable if we knew, for example, that the Height is twice the Length. Then the formula would become: L2 + 4L2 = 260 L2 = 52 L = 7.211 cm
