Q: What would the volume of a garden that is 4' X 8'X10?

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6 feet 6+6+4+4 = 20

the volume of a sphere is 4/3 (pi) r^3, so if r= 9 then volume would be approximately 3053.63m

The volume of a 6 x 4 x 5 inch rectangular prism is the product of those four values. The answer is 120.

Tables of 8 or 4 or 2 72 = 8x9 or 4x18 or 2x36 80 = 8x10 or 4x20 or 2x40

Volume of a sphere is 4/3 * pi * r cubed. Radius being 5 feet you would do:(4 / 3) * pi * 125 = 523.598776 feet, which in metric would be 159.592907 metres.

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Water would pour into your garden as soon as its level was greater than 4 feet. It would continue to pour in until the level of the water above the ground level of your garden subsided to below 4 feet. THis may or may not happen. It would depend on the volume of water available to fill the surrounding area to a depth greater than 4 feet.

2/4

The volume of a sphere is given by V = (4/3)πr^3. The nucleus volume is (4/3)π(5^3) and the atom volume is (4/3)π(10^4)^3. The fraction of the atom's volume taken up by the nucleus is [(4/3)π(5^3)] / [(4/3)π(10^4)^3] which simplifies to (5^3) / (10^4)^3 = 1/8000.

yes the volume would inrease!!!

The volume would be reduced by a factor of 64.

wall garden is the an enclosed garden with 4 words.

If the shape is a rectangular prism (cuboid), the volume is 6*4*5 = 120 cubic units.

You use perimeter when you are making a fence

Volume would be 5.118 gallons of liquid.

A local realtor can answer your question. There is no standard.

Comparable, Yes, but they have no hope of matching the detail using one exposure. Exposure to print would be so much simpler with the digital. Since 8x10 enlargers are not terribly common, a contact print is usually all that is done. At 8x10 size the digital could equal or better the 8x10 negatives print in both archival characteristics and simplicity. No need to even get your hands wet! A print bigger than 8x10 would be phenomenally better if done from the 8x10 neg and using the enlarger. ******* If you are considering such a camera, there is a lot more at stake than technical image quality which you allude to. I feel safe in saying no 35mm camera will provide the control possible with the field camera, and then there is the whole purist thing. Perhaps you have read this essay? http://www.wisner.com/digital.htm

Vcone = πr2h/3 Doubling r would multiply volume by 22 = 4 4 * 225 ft3 = 900 ft3