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You would need to know other physical properties to be able to calculate the length. As you would need to know certain properties to be able to calculate the volume, for instance.
You would need a balance to measure its mass. You would need a ruler to measure the length of its sides. Then you would need to calculate volume. Then divide the mass by the volume to get density.
The shape of an object is not enough to calculate its density. You also need its mass and then Density = Mass/Volume.
Not enough information. To calculate mass, you would need volume and density (mass = volume x density).
You would need a 3rd dimension to calculate a volume.
To calculate the molality of a solution, you need to know the moles of solute (in this case, NaCl) and the mass of the solvent (water). First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality using the formula molality = moles of solute / mass of solvent in kg.
To calculate the molality of a solution, you need to know the moles of solute and the mass of the solvent in kilograms. First, calculate the moles of NaCl in 0.2 kg: moles = mass (g) / molar mass. Then, calculate the molality by dividing the moles of solute by the mass of solvent in kg: molality = moles of solute / mass of solvent in kg.
Convert the 200 mol of water to kilograms of water.
Convert the 200 mol of water to kilograms of water.
To calculate the molality of a solution, you would first convert the mass of NaCl to moles, then divide by the mass of the solvent in kilograms. In this case, you would convert 10 g NaCl to moles, which is 0.17 moles. Then, divide that by the mass of water in kg (2 kg) to get the molality of NaCl in the solution.
To calculate molality, we first need to find the moles of AgClO4 and the moles of solvent, C6H6. Calculate moles of AgClO4: 75.2 g / molar mass of AgClO4 Calculate moles of C6H6: 885 g / molar mass of C6H6 Then, molality (m) = moles of solute / kg of solvent. Divide the moles of AgClO4 by the kg of C6H6 to find the molality of the solution.
58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
Convert the 200 mol of water to kilograms of water.
To calculate the molality, first calculate the moles of Cl2: Moles of Cl2 = 16.1 g / (35.45 g/mol + 35.45 g/mol) = 0.227 moles. Then, molality = moles of solute / mass of solvent in kg: molality = 0.227 moles / (5000 g / 1000) = 0.0454 mol/kg.
To calculate the molality of the solution, you first need to find the molar mass of NaCl, which is 58.44 g/mol. Next, calculate the mass of NaCl in 1 L of the solution by multiplying the density (1.25 g/mL) by 1000 mL. Then divide the mass of NaCl by the molar mass to find the number of moles. Finally, divide the moles by the mass of the solvent (in kg) to get the molality. In this case, the molality is approximately 1.30 mol/kg.
0.33 mol/kg
To calculate the molality of the solid solution, you need to first find the moles of chromium and iron separately. Then, determine the total moles of solute (chromium) and solvent (iron). Finally, divide the moles of solute by the mass of the solvent (in kg) to get the molality. Molality (m) = moles of solute / mass of solvent (kg).