To calculate the molality of 10 g of NaCl in 2 kg of water, you need to determine the number of moles of NaCl and the mass of the solvent (water) in kilograms. First, calculate the molar mass of NaCl, which is approximately 58.44 g/mol. Then, divide the mass of NaCl (10 g) by its molar mass to find the number of moles, and finally, use the formula for molality: molality = moles of solute / mass of solvent (in kg). In this case, the calculation would be molality = (10 g / 58.44 g/mol) / 2 kg.
There are no atoms in NaCl . (Sodium Chloride) . They are all combined together as ions. Na^(+) & Cl^(-) The ratio of positive ion to negative ions is 1:1 NB An atom is an neutral (uncharged) species. An ion is an atom that has lost or gained electrons, and thereby becoming a charged species.
To calculate the molality of a solution, you need to divide the moles of the solute (in this case, NaCl) by the mass of the solvent (water) in kilograms. First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality by dividing the moles of NaCl by the mass of water in kilograms.
NaCI + H20 NaCI- Sodium Chloride-Salt. H20 is obviously Di-Hydrogen Oxide. Water.
Its a mixture
To calculate the molarity of 10 g of NaCl in 2 kg of water, you would first need to convert the mass of NaCl to moles using its molar mass. Then, calculate the total volume of the solution by considering the density of water (1 kg = 1 L). Finally, divide the moles of NaCl by the volume of the solution in liters to determine the molarity.
The van't Hoff factor for NaCl is 2 since it dissociates into 2 ions in water. The freezing point depression constant for water is 1.86 °C kg/mol. By using the formula ΔTf = i * Kf * m, where i is 2, Kf is 1.86, and m is the molality of the solution (4 mol / 1 kg = 4 m), the freezing point of water will decrease by 14.88 °C.
it is an ionic compound.
It dissolves in water
using the initial mass of the NaCI and SiO2 mixture from part A as well as the mass of the dry NaCI recovered from part B, calculate the expert value of the percent composition by mass of NaCI in the mixture
Please explain 10 !
Change in boiling point = (i)(m)(K)i = van't Hoff factor which for NaCl is 2 (2 particles form upon ionization) m = molality = moles/kg = 4 moles/1 kg = 4 K = boiling point constant for water = 0.512 degrees/m ∆T = (2)(4)(0.512) = 4.1 degrees So, the boiling point of water would increase by 4.1 degrees C (4 degrees to 1 sig. fig.)
Naci Eldeniz was born in 1875.
Naci Taşdöğen was born in 1967.