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It is (2x-5)(x-4) when factored
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
2x^8 -16x^7 +10x^6 = 2x^6(x^2 - 8x + 5)
Let the number be x: So: 2x-4 = x-10 => 2x-x = 4-10 => x = -6
Well it depends on what you mean, in math terms will usually mean the parts of an expression that are added or subtracted but not multiplied. Ex. 3x^2+2x+4 The terms here are 3x^2, 2x, and 4.