It is (2x-5)(x-4) when factored
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
2x^8 -16x^7 +10x^6 = 2x^6(x^2 - 8x + 5)
Let the number be x: So: 2x-4 = x-10 => 2x-x = 4-10 => x = -6
Well it depends on what you mean, in math terms will usually mean the parts of an expression that are added or subtracted but not multiplied. Ex. 3x^2+2x+4 The terms here are 3x^2, 2x, and 4.
It is (2x-5)(x-4) when factored
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
7 - 2x = 11 2x = 7 - 11 = -4 Therefore, x = -2
2X - 4 = -10 2X = -6 X = -3
2x^8 -16x^7 +10x^6 = 2x^6(x^2 - 8x + 5)
2x + 7 - 3 = 0 ie 2x + 4 = 0 2x = -4 x = -2
3-2x=7 so -2x=4 and x=-2
Let the number be x: So: 2x-4 = x-10 => 2x-x = 4-10 => x = -6
2(10x6) 4(5x3)
Well it depends on what you mean, in math terms will usually mean the parts of an expression that are added or subtracted but not multiplied. Ex. 3x^2+2x+4 The terms here are 3x^2, 2x, and 4.
It is negative 34.
Suppose the three integers are 2x-2, 2x and 2x+2 for some integer x. Then 4*(2x-2) - (2x+2) = 2*2x + 6 or 8x - 8 - 2x - 2 = 4x + 6 => 6x - 10 = 4x + 6 => 2x = 16 so that x = 8. So the numbers are 14, 16 and 18.