Wiki User
∙ 14y ago245.7
Wiki User
∙ 14y agoChange in temperature = New temperature minus Old temperature.
pi is the circumference divided by the diameter. it is a set universal constant and will never change = 3.1415...
No. The units don't matter, the circumference always equals pi times the diameter. (This is only true of the circumference and diameter are in the same units. If for example, the circumference was in feet and the diameter in inches, the feet must be change to inches or the inches to feet in order for this relationship to be true.)
Heat energy Q = mass x specific heat capacity x temperature change. Q = m*c*delta T Q = Joules m = kg c (aluminum) = 895.8 J/kg delta T = degr.C temp. change Answer: Q = (20/1000) x 895.8 x 5 = 89.58 Joules (Specific heat capacity of aluminum is obtained by multiplying its specific heat of 0.214 with c of water which is 4186 J/kg = 0.214 x 4186 = 895.8 J/kg).
It will make the circumference of the circle bigger or smaller
Using the specific heat capacity of aluminum (0.897 J/g°C), you can calculate the change in temperature using the formula Q = mcΔT, where Q is the heat absorbed (725J), m is the mass of aluminum block (55g), c is the specific heat capacity, and ΔT is the change in temperature. Rearranging the formula to solve for ΔT and substituting the values, you can then find the final temperature by adding the change in temperature to the initial temperature (27.5°C). Calculate and the final temperature of the aluminum block will be the sum of the initial temperature and the change in temperature.
possibly, it can into a liquid!
Starting from the same temperature and for the same amount of heat input, aluminum would wind up with a higher temperature than water because water has a higher heat capacity (it takes more energy to raise its temperature) than aluminum.
The specific heat capacity of aluminum is 0.897 J/g°C. To calculate the energy required to heat 0.5kg of aluminum by a certain temperature change, you would use the formula: Energy = mass x specific heat capacity x temperature change If you have the temperature change, you can plug the values into the formula to find the total energy in joules.
To find the final temperature, you can use the principle of conservation of energy, Q lost = Q gained. The heat lost by the aluminum will be equal to the heat gained by the water. Use this formula: (mass of aluminum) x (specific heat capacity of aluminum) x (change in temperature) = (mass of water) x (specific heat capacity of water) x (change in temperature). You can then solve for the final temperature.
The volume change of a sphere can be calculated using the formula V = 4/3 * π * r^3, where r is the radius. The temperature change required to increase the volume can be calculated using the coefficient of thermal expansion of steel. The diameter of the steel ball bearing at 100°C can be calculated using the volume change and the new temperature, considering the change in radius.
Aluminum needs less energy than lead to raise its temperature by one degree, as aluminum has a lower specific heat capacity compared to lead. This means that aluminum can absorb and release heat more easily than lead for the same change in temperature.
Yes, it is possible to change the color of aluminum foil by applying heat to it. When heated, the oxide layer on the surface of the aluminum can change color based on the temperature, creating a rainbow effect. However, prolonged exposure to high temperatures can cause the foil to deteriorate.
Aluminum has more thermal energy compared to gold because aluminum has a higher specific heat capacity, meaning it can absorb and retain more heat energy for a given temperature change.
When aluminum is cooled from 3000 to 2000 degrees Fahrenheit, it undergoes a solidification phase change from liquid to solid. Aluminum solidifies at around 1220 degrees Fahrenheit, so this decrease in temperature would cause the molten aluminum to solidify.
A chemical change of aluminum would be its reaction with oxygen to form aluminum oxide. This reaction involves the breaking and forming of chemical bonds, resulting in a new substance with different properties than the original aluminum.
The radius is half the diameter.