If the area was 0, there would be no triangle.
It is impossible to find the area of a triangle with no height, if the triangle had no height it would not even be a triangle, just a angle.
further informations is needed to solve this problem. the area of a triangle is: .5bh plugging in 48 as the area and trying to solve would leave two unknowns.
to find the area of a triangle you divide the base of the triangle by two and multiply your answer by the height .so your formula would be 1/2b times h to find the perimeter of a triangle u simply just add the sides.
The area of triangle is : 24.0
This sentence can be complete as: After a congruence transformation the area of a triangle would be the same as it was before.
A congruence transformation of a shape is one that does not alter the size (area) or the relative lengths and positions of the lines.Translations, rotations and reflections are all example of simple transformations which are congruent.
If the area was 0, there would be no triangle.
The area of the triangle would double
You define a function with an return value. The return value would be the area of the triangle, and the parameters are the width/length and height of the triangle. Inside the function you would define how you would calculate the area, and then return the result.
Triangle-least area, circle- most area, per given perimeter . The circle would have an area of 154 square cm. the triangle could have an area of almost zero if it were a long, skinny triangle. An equilateral triangle would have an area approx 92.8 sq cm.
The area of a triangle does not provide enough information to answer the question. The triangle could be thin and tall or broad-based and short and have the same area.
It is impossible to find the area of a triangle with no height, if the triangle had no height it would not even be a triangle, just a angle.
Area = 0.5*base*height Note that the given dimensions would not form a triangle
It would be called the midsegment of the triangle. And when you have all the midpoints of the triangle joined, you would get the midsegment triangle. It is one fourth of the area of the actual triangle
Doubling those two dimensions would quadruple the area. So new area = 4*34 cm2 = 136 cm2
It depends on the shape of the face. Congruence is of no help in this respect.