Impossible. Anything divided by 1 is itself.
The smallest 4 digit number divisible by 50 is 1000, so to have a remainder of 17, it is 1000 + 17 = 1017.
55 52+52 = 50
1/80
A multiple of 50 is any number in the 50 times table. So the 3 digit multiples of 50 are: 100, 150, 200 ... 850, 900, 950.
50
10017
4000
1017
The smallest 4 digit number divisible by 50 is 1000, so to have a remainder of 17, it is 1000 + 17 = 1017.
The number 50 is composite. Any two-digit (or more-digit) number that ends in zero can be divided evenly by 10 (and 5 and 2, for that matter). That means no two- or more-digit number ending in 0 can be prime.
55 52+52 = 50
100
1/80
A multiple of 50 is any number in the 50 times table. So the 3 digit multiples of 50 are: 100, 150, 200 ... 850, 900, 950.
50
If its squared rott is 50, the number must be 2500, which is not a 2-digit number.
50