To find the product of a 2-digit number and a 4-digit number that is approximately 500,000, we need to consider the magnitude of the numbers involved. Since a 2-digit number ranges from 10 to 99 and a 4-digit number ranges from 1000 to 9999, their product will be in the range of 10,000 to 99,000,000. To get a product around 500,000, we can estimate that the 2-digit number is around 50 and the 4-digit number is around 10,000. Therefore, the product of a 50 and 10,000 is 500,000.
The only three-digit number that fits the criteria of being a square number and having a product of its digits equal to two is 128. This is because 128 is a square number (11^2 = 121, 12^2 = 144) and the product of its digits (1 x 2 x 8) equals 16, which is not equal to two. Therefore, there is no three-digit number that meets all the given conditions.
Yes, unless the 3 digit number is negative, or a decimal.
example-99/33=3
By using the 3 digits of a number we can form 3 different two digit numbers. 3C2 = 3!/[(3 - 2)!2!] = 3!/(1!2!) = (3 x 2!)/2! = 3
For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.
2 digit number
-2
It is 891.
Since the greatest digit is 9 and the greatest 2-digit number is 99, the product of them is 891.
2
Nothing in this universe: 16,25,36,49,64 & 81 are the only 2-digit squares.
Six.
It is: 97*2 = 194
98,901
1000
99*999 = 98901
24